標(biāo)題:
利用單片機中斷延時消除按鍵抖動
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作者:
883
時間:
2019-9-5 12:37
標(biāo)題:
利用單片機中斷延時消除按鍵抖動
利用delay()的延時消除按鍵抖動,用while(!K)等語句檢測松手動作,這種按鍵處理程序,簡單易懂,許多初學(xué)者喜歡使用。但如果程序端口有檢測信號的話,十幾二十毫秒的延時錯過了不少檢測信號。如果按鍵一直按著或按鍵損壞短接了,程序就會一直停留在這里不能運行了。設(shè)置2毫秒的中斷延時,利用中斷延時避開主程序過長的周期。將按鍵檢測分為兩種狀態(tài),在檢測按鍵按下狀態(tài)中完成延時消抖,后進入檢測按鍵松開。
水平有限,貼上程序大家共同探討。
單片機源程序如下:
#include <reg52.h>
typedef signed long slong;
typedef signed int sint;
typedef signed char schar
typedef unsigned long ulong;
typedef unsigned int uint;
typedef unsigned char uchar;
#define SEG_DB P0 //數(shù)碼管
sbit SEG_WE = P2^7; //數(shù)碼管位選
sbit SEG_DU = P2^6; //數(shù)碼管段選
sbit Keyin1 = P3^4;
//sbit Keyin2 = P3^5;
//sbit Keyin3 = P3^6;
//sbit Keyin4 = P3^7;
sbit Keyout1 = P3^0;
//sbit Keyout2 = P3^1;
//sbit Keyout3 = P3^2;
//sbit Keyout4 = P3^3;
bit Keytan=1;
uchar T0RH,T0RL;
uchar Ledtmp[6];
uint cou;
uchar code Ledchar[] = {0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d,0x07,
0x7f,0x6f,0x77,0x7c,0x39,0x5e,0x79,0x71};
void ConfigTimer0(uchar ms);
void KeyDrive();
void main()
{
schar j;
uchar buf[6];
Keyout1 = 0;
ConfigTimer0(2);
Ledtmp[0] = Ledchar[2];
while (1)
{
KeyDrive();
buf[0] = cou%10;
buf[1] = cou/10%10;
buf[2] = cou/100%10;
buf[3] = cou/1000%10;
buf[4] = cou/10000%10;
buf[5] = cou/100000%10;
for (j=5;j>=1;j--) //消隱高位數(shù)的0
{
if (buf[j] == 0)
Ledtmp[j] = 0x00;
else
break;
}
for (;j>=0;j--)
{
Ledtmp[j] = Ledchar[buf[j]];
}
}
}
void KeyDrive()
{
static Keybuf = 1;
if (Keybuf != Keytan)
{
if (Keybuf == 1)
{
cou++;
}
Keybuf = Keytan;
}
}
void LedPlay()
{
static uchar i=0;
SEG_DB = 0xff;
SEG_WE = 1;
SEG_WE = 0;
SEG_DB = Ledtmp[i];
SEG_DU = 1;
SEG_DU = 0;
SEG_DB = ~(0x20>>i);
SEG_WE = 1;
SEG_WE = 0;
i++;
if (i == 6)
i = 0;
}
void KeyScan()
{
static uchar kmode=0;
static uchar i;
switch (kmode)
{
case 0: if (Keyin1 == 0) //檢測按鍵按下
{
i++;
if (i == 7) //7次相當(dāng)于延時2msx7=14毫秒
{
i = 0;
kmode = 1; //按鍵穩(wěn)定,轉(zhuǎn)換進入檢測按鍵松手模式
Keytan = 0; //按鍵動作標(biāo)志
}
}
else
i = 0; //沒有7次連續(xù)檢測到按鍵按下,說明沒有穩(wěn)定,時間清零
case 1: if (Keyin1 == 1) //檢測按鍵松開
{
Keytan = 1; //按鍵松開標(biāo)志
kmode = 0; //進入檢測按鍵按下模式
}
}
}
void ConfigTimer0(uchar ms)
{
ulong tmp;
tmp = 11059200/12;
tmp = (tmp*ms)/1000;
tmp = 65536 - tmp;
T0RH = (uchar)(tmp>>8);
T0RL = (uchar)tmp;
TH0 = T0RH;
TL0 = T0RL;
TMOD &= 0xf0;
TMOD |= 0x01;
TR0 = 1;
ET0 = 1;
EA = 1;
}
void InterruptTimer0() interrupt 1
{
TH0 = T0RH;
TL0 = T0RH;
LedPlay();
KeyScan();
}
復(fù)制代碼
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按鍵.zip
(39.04 KB, 下載次數(shù): 11)
2019-9-5 12:36 上傳
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