標(biāo)題:
一個單片機(jī)秒表程序,哪里出錯了?error C141: syntax error near 'SCL'
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作者:
廖振基
時間:
2022-1-11 15:44
標(biāo)題:
一個單片機(jī)秒表程序,哪里出錯了?error C141: syntax error near 'SCL'
一個51單片機(jī)秒表程序,編譯提示:SCL附近語法錯誤, 在第87行。 才接觸單片機(jī)不久,小白一個,怎么也找不到,敬請高手指點(diǎn)指點(diǎn)。
AA.C(87): error C141: syntax error near 'SCL'
AA.C(114): error C141: syntax error near 'write_byte'
Target not created
請高手看看哪里出錯了?
單片機(jī)源程序如下:
#include"reg52.h"
#define uchar unsigned char
#define uint unsigned int
bit write=0;
sbit SDA=P2^0;
sbit SCL=P2^1;
uchar code table[]={0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d,0x07,0x7f};
uchar sec, tcnt;
void delay()
{;;}
void delay1ms(uint z)
{ uint x, y;
for(x=z;x>0;x--)
for(y=110;y>0;y--);
}
void start() //開始信號
{
SDA=1;
delay();
SCL=1;
delay();
SDA=0;
delay();
}
void stop() //停止
{
SDA=0;
delay();
SCL=1;
delay();
SDA=1;
delay();
}
void respons() //應(yīng)答
{
char i;
SCL=1;
delay();
while((SDA==1)&&(i<250))i++;
SCL=0;
delay();
}
void init()
{
SDA=1;
delay();
SCL=1;
delay();
}
void write_byte(uchar date) //寫
{
uchar i,temp;
temp=date;
for(i=0;i<8;i++)
{
temp=temp<<1;
SCL=0;
delay();
sda=CY;
delay();
SCL=1;
delay();
}
SCL=0;
delay();
SDA=1;
delay();
}
uchar read_byte() //讀
{
uchar i,k;
SCL=0;
delay();
SDA=1;
delay();
for(i=0;i<8;i++)
{
SCL=1;
delay();
k=(k<<1)|sda
SCL=0; // 這里報;scl附近語法錯誤。
delay();
}
return k;
}
void write_add(uchar address,uchar date)
{
start();
write_byte(0xa0);
respons();
write_byte(address);
respons();
write_byte(date);
respons();
stop();
}
uchar read_add(uchar address)
{
uchar date;
start();
write_byte(0xa0);
respons();
write_byte(address);
respons;
start()
write_byte(0xa1);
respons;
date=rede_byte();
stop();
return date;
}
void display(uchar bai_c, uchar sh_c)//顯示
{
P0=table[bai_c]; //顯示第一位
P1=0xff;
delay1ms(5);
P0=table[sh_c];
P1=0xfe;
delay1ms(5);
}
void main()
{
init();
sec=read_add(2); //讀出保存的數(shù)據(jù)賦予sec
if(sec>100) //防止首次讀取出錯
sec=0;
TMOD=0x01; //定時器工作方式1
ET0=1; //存疑
EA=1;
TH0=(65536-5000)/256; //賦值
TL0=(65536-5000)%256 ;
TR0=1; //開始計(jì)時
while(1)
{
display(sec/10,sec%10);
if(wtite==1) //判斷計(jì)時器是否計(jì)時一秒
{
write=0; //清0
write_add(2,sec); //再24C16寫數(shù)據(jù)
}
}
}
void t0()interrupt 1 //定時中斷程序
{
TH0=(65536-50000)/256; //賦值
TL0=(65536-50000)%256;
tcnt++; //每過50ms,tcnt加1
if(tcnt=20) //計(jì)滿20時
{
tcnt=0; //重新再計(jì)
sec++;
write=1; //一秒寫一次24C16
if(sec==100) //定時100秒,再從0開始
sec=0;
}
}
復(fù)制代碼
作者:
huashanhui20
時間:
2022-1-11 21:06
錯誤太多了,86行113行少分號,112行和115行少括號,其它自己再找找
作者:
廖振基
時間:
2022-1-12 13:21
謝謝指導(dǎo),又找到幾個語法錯誤后,終于運(yùn)行了.
歡迎光臨 (http://www.torrancerestoration.com/bbs/)
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