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#include "STC15F2K60S2.H"
#define uint unsigned int
#define uchar unsigned char
//P0腳是輸出段碼，單片機驅動電流小，要加上拉電阻
sbit LED_D1 = P1^6;//第1位數(shù)碼管
sbit LED_D2 = P1^5;//第2位數(shù)碼管
sbit LED_D3 = P1^4;//第3位數(shù)碼管
sbit LED_D4 = P1^7;//第4位數(shù)碼管
sbit LED_D5 = P1^3;//第5位數(shù)碼管
sbit LED_D6 = P1^2;//第6位數(shù)碼管
sbit LED_D7 = P1^1;//第7位數(shù)碼管
sbit LED_D8 = P1^0;//第8位數(shù)碼管
// 0 1 2 3 4 5 6 7 8 9 -
uchar code table[]={0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d,0x07,0x7f,0x6f,0x40}; //共陰數(shù)碼管字段碼
uchar D_word[8];//各個位上的數(shù)字的緩存
void Delay_1ms(uint i) //延時函數(shù)
{ uchar x,j;
for(j=0;j<i;j++)
for(x=0;x<=10;x++)
;
}
void display(unsigned long display_temp) //數(shù)碼管顯示程序
{
uchar i=0;
for(i=0;i<8;i++) //這塊LCD可以顯示4位數(shù)，逐位拆分要轉換的數(shù)字
{
D_word[i] = display_temp%10; //個位取模求余數(shù)，即得個位上的數(shù)字
display_temp /= 10; //要轉換的數(shù)字除10求整數(shù)，即是整體向右移一位,下次求余即得十位上的數(shù)字，如此類推
}
/***************第一至四位數(shù)碼管*******************************/
P0 = table[D_word[7]];
LED_D1= 0;
Delay_1ms(2);
LED_D1=1;
P0 = table[D_word[6]];
LED_D2= 0;
Delay_1ms(2);
LED_D2=1;
P0 = table[D_word[5]];
LED_D3= 0;
Delay_1ms(2);
LED_D3=1;
P0 = table[D_word[4]];
LED_D4= 0;
Delay_1ms(2);
LED_D4=1;
/****************第五至八位數(shù)碼管**********************************/
P0 = table[D_word[3]];
LED_D5 = 0;
Delay_1ms(2);
LED_D5=1;
P0 = table[D_word[2]];
LED_D6 = 0;
Delay_1ms(2);
LED_D6=1;
P0 = table[D_word[1]];
LED_D7 = 0;
Delay_1ms(2);
LED_D7=1;
P0 = table[D_word[0]];
LED_D8 = 0;
Delay_1ms(2);
LED_D8=1;
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