keil報(bào)錯(cuò)ERROR L121 (IMPROPER FIXUP)

ID:307417 · 發(fā)表于 2018-5-9 18:59

之前找的一份資料里的程序，想改程序時(shí)卻出現(xiàn)了ERROR L121 (IMPROPER FIXUP)的情況，不知道該怎么解決。不過(guò)資料里確實(shí)有HEX文件，我也稍微了解了一下，可能是keil版本高的原因，我用的是keil5.

ID:307417 · 發(fā)表于 2018-5-9 19:08

#include "keyboard.h"
extern bit bdata flag_key;
//按鍵掃描函數(shù) :
//功能；只掃描一個(gè)按鍵，按鍵為號(hào)小優(yōu)先
//返回鍵值：
//       1 2 3 10    //10:清零重量，兼去皮功能
//       4 5 6 11    //11:清除單價(jià)
//       7 8 9 12    //12:顯示數(shù)值偏大調(diào)節(jié)按鍵
//       14 0 15 13    //14:無(wú)功能（用于擴(kuò)展）15：小數(shù)點(diǎn) 13：顯示數(shù)值偏小調(diào)節(jié)按鍵

unsigned char Getkeyboard(void)
{
unsigned char number = 0;
unsigned char i;
//行輸入低電平
ROW1=ROW2=ROW3=ROW4=0;
//如果列輸出不全為高，則說(shuō)明有鍵按下
if (((COL1!=1)||(COL2!=1)||(COL3!=1)||(COL4!=1))&&flag_key==1)
{
   //輸入0111
   flag_key=0;
   ROW1=0;
   ROW2=ROW3=ROW4=1;
   for (i=0;i<20;i++);
   if (COL1==0) return 1;    // 7
   else if (COL2==0) return 2; //    8
   else if (COL3==0) return 3;    // 9
   else if (COL4==0) return 10;    //    10
   //輸入1011
   ROW2=0;
   ROW1=ROW3=ROW4=1;
   for (i=0;i<20;i++);
   if (COL1==0) return 4;    //4
   else if (COL2==0) return 5; //  5
   else if (COL3==0) return 6; // 6
   else if (COL4==0) return 11;    // 11
   //輸入1101
   ROW3=0;
   ROW1=ROW2=ROW4=1;
   for (i=0;i<20;i++);
   if (COL1==0) return 7;  //1
   else if (COL2==0) return 8;    // 2
   else if (COL3==0) return 9;    // 3
   else if (COL4==0) return 12;    // 12
   //輸入0111
   ROW4=0;
   ROW1=ROW2=ROW3=1;
   for (i=0;i<20;i++);
   if (COL1==0) return 14;
   else if (COL2==0) return 0;
   else if (COL3==0) return 15;
   else if (COL4==0) return 13;
   //沒(méi)有檢測(cè)到列低電平
   return 99;
}
else if(COL1==1&&COL2==1&&COL3==1&&COL4==1)
flag_key=1;
return 99;
}

ID:307417 · 發(fā)表于 2018-5-10 09:51

qq8281212 發(fā)表于 2018-5-9 19:42
書(shū)上有解釋

請(qǐng)問(wèn)一下是哪本書(shū)

ID:328014 · 發(fā)表于 2021-1-10 23:44

我今天也遇到了同樣的問(wèn)題,IMPROPER FIXUP,研究了半天終于解決了,原來(lái)這個(gè)問(wèn)題是因?yàn)镵eil4和Keil5不支持bdata的問(wèn)題導(dǎo)致的,所以退回Keil2,新建工程,加入文件,重新編譯就OK了,你這個(gè)上面也有bdata所以也可以用我的辦法來(lái)成功解決的.

參考資料:
The variables ibase and bary are bit-addressable. Therefore, the individual bits of these variables may be directly accessed and modified. Use the sbit keyword to declare new variables that access the bits of bdata variables. For example:

sbit mybit0 = ibase ^ 0;    /* bit 0 of ibase */
sbit mybit15 = ibase ^ 15; /* bit 15 of ibase */

sbit Ary07 = bary[0] ^ 7;    /* bit 7 of bary[0] */
sbit Ary37 = bary[3] ^ 7;    /* bit 7 of bary[3] */
The above example represents declarations, not assignments to the bits of the ibase and bary bdata variables. The expression following the carat symbol ('^') in the example specifies the position of the bit to access with this declaration. This expression must be a constant value.

The range depends on the type of the base variable included in the declaration. The range is:

0-7 for char and unsigned char, 0-15 for int, unsigned int,
short, and unsigned short, and
0-31 for long and unsigned long.

并沒(méi)有定義bit類型的bdata。因此定義成char。

OFDM_PHY_ext char    bdata bLib_RxPlcEnd;
OFDM_PHY_ext char    bdata  RX_BUSY;
OFDM_PHY_ext char    bdata  TX_BUSY;
Comm_ext char bdata bCommRxEnd;
Comm_ext char bdata bCommRxstart;

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