求救��！數(shù)碼管顯示AD值

高手們大俠們父老鄉(xiāng)親們都來看看程序吧   在用3位數(shù)碼管顯示連續(xù)變化的AD值，我寫的程序怎么就是實(shí)現(xiàn)不了啊，求救。

#include<reg51.h>
#define uchar unsigned char
sbit oe=P1^0;
sbit eoc=P1^1;
sbit st=P1^2;
sbit clk=P1^3;
sbit led2=P2^1;
sbit led3=P2^2;
sbit led4=P2^3;
  int ad_out;
  int div_buf;
  int div[2]; //16????×a10????μ?3??°???ê?3?￡?ò2ê?LEDμ??o′?ê?3?  
  int xdata *DPTR; 
  
void timer(void) interrupt 1 using 0
{
 clk=!clk;
}
void delay(uchar z) 
{ 
 int i; 
 for(i=0;i<=z;i++);         
    
}
led()
{
 switch(div_buf)
  {
   case 0: return(0xc0); break; //êy??1ü12??
   case 1: return(0xf9); break;
   case 2: return(0xa4); break;
   case 3: return(0xb0); break;
   case 4: return(0x99); break;
   case 5: return(0x92); break;
   case 6: return(0x82); break;
   case 7: return(0xf8); break;
   case 8: return(0x80); break;
   case 9: return(0x90); break;
   }
}
void output()
{

  led2=1;led3=0;led4=0; //μú2??êy??1ü
  div_buf=div[0];
  P0=led();
  delay(123);
  
 
  led2=0;led3=1;led4=0;//μú3??êy??1ü
  div_buf=div[1];
  P0=led();
  delay(123);
  
  led2=0;led3=0;led4=1;//μú4??êy??1ü
  div_buf=div[2];
  P0=led();
  delay(123);
 
  
  led2=1;led3=1;led4=1;
  
  delay(1230000);
    
}

void main(void)
{
   
   int num=0,j=1;
    TMOD=0x02;//T0·?ê?2
    TH0=0xff;
 TL0=0xff;
    TR0=1;
 EA=1;
 ET0=1;

   while(1)
   {
    DPTR=0x0000;
 *DPTR=0x00;
    delay(123);
 
    st=1;
 st=0;
 st=1;
 while(eoc==1);//μè′y×a??
    {
 oe=1;
 ad_out=P3;
    oe=0; 

      div[0]=ad_out/100;

      div[1]=ad_out%100/10;

      div[2]=ad_out%10;
  }
    output();
 
   }
}


 

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原理圖.rar (95.02 KB, 下載次數(shù): 22)

2011-9-24 16:06 上傳

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