我自己用8×8連16×16，為什么不能用啊，只有第八行和第16行亮

ID:446674 · 發(fā)表于 2018-12-25 09:16

請說清楚問題，發(fā)照片、程序、電路圖

ID:155507 · 發(fā)表于 2018-12-25 09:25

程序呢?線路圖呢?什么都沒有,人家想幫你也幫不上呀

我給你來個試試

/*-----------------------------------------------
名稱：595控制4漢字點(diǎn)陣屏
修改：無 51單片機(jī)
內(nèi)容：屏+5V、GND連接電源5V
P0.0-P0.3分別連接A、B、C、D，用于控制16行，通過2路HC138控制
SCK時鐘連接P2.5
LATCH鎖存連接P2.6
R1紅色數(shù)據(jù)信號連接至P0.4
G1綠色數(shù)據(jù)信號連接至P2.4，如果使用單紅色屏此信號無需連接
OE使能端一般接GND，可以用IO引腳PWM控制亮度
或者使用此引腳控制拖尾現(xiàn)象。
現(xiàn)象：使用普通速度51系列單片機(jī)。單個漢字屏出現(xiàn)紅色“德”
------------------------------------------------*/
#include<reg52.h>
sbit T_STR = P2^6; //鎖存引腳，屏上標(biāo)識位STR
sbit R1 = P0^4; //數(shù)據(jù)引腳，屏上標(biāo)識R1
sbit G1 = P2^4; //數(shù)據(jù)引腳，屏上標(biāo)識G1
sbit T_CLK = P2^5; //時鐘引腳，屏上標(biāo)識位CLK
sbit OE = P2^1; //使能引腳，屏上標(biāo)識EN/OE
unsigned char tab[8];
unsigned char DIS[]={0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15};//行數(shù)據(jù)
/*-----------------------------------------------
16x16漢字取模數(shù)據(jù)
------------------------------------------------*/
unsigned char code hztest[][32]= //二維數(shù)組，目的是減少運(yùn)算，可以用最基本的一維數(shù)組，每個漢字有32個字節(jié)數(shù)據(jù)
{
/*-- 文字: 德 --*/
/*-- 宋體12; 此字體下對應(yīng)的點(diǎn)陣為：寬x高=16x16 --*/
0x08,0x02,0x08,0x02,0xF4,0x7F,0x02,0x02,0xE9,0x3F,0x28,0x25,0x24,0x25,0xE6,0x3F,
0x05,0x00,0xF4,0x7F,0x04,0x02,0x04,0x24,0xA4,0x44,0xA4,0x50,0x94,0x10,0x04,0x1F,
/*-- 文字: 飛 --*/
/*-- 宋體12; 此字體下對應(yīng)的點(diǎn)陣為：寬x高=16x16 --*/
0x00,0x00,0xFF,0x03,0x00,0x02,0x00,0x22,0x00,0x12,0x00,0x0A,0x00,0x06,0x00,0x0A,
0x00,0x12,0x00,0x22,0x00,0x04,0x00,0x04,0x00,0x48,0x00,0x50,0x00,0x60,0x00,0x40,
/*-- 文字: 萊 --*/
/*-- 宋體12; 此字體下對應(yīng)的點(diǎn)陣為：寬x高=16x16 --*/
0x10,0x04,0x10,0x04,0xFF,0x7F,0x90,0x04,0x80,0x00,0xFC,0x1F,0x80,0x00,0x88,0x08,
0x90,0x04,0xFE,0x3F,0xC0,0x01,0xA0,0x02,0x90,0x04,0x8C,0x18,0x83,0x60,0x80,0x00,

復(fù)制代碼

ID:155507 · 發(fā)表于 2018-12-25 10:03

/*-----------------------------------------------
名稱：595控制4漢字點(diǎn)陣屏
修改：無 51單片機(jī)
內(nèi)容：屏+5V、GND連接電源5V
現(xiàn)象：使用普通速度51系列單片機(jī)。單個漢字屏出現(xiàn)紅色“德”
------------------------------------------------*/
#include<reg52.h>
sbit T_STR = P2^6; //鎖存引腳，屏上標(biāo)識位STR
sbit R1 = P0^4; //數(shù)據(jù)引腳，屏上標(biāo)識R1
sbit G1 = P2^4; //數(shù)據(jù)引腳，屏上標(biāo)識G1
sbit T_CLK = P2^5; //時鐘引腳，屏上標(biāo)識位CLK
sbit OE = P2^1; //使能引腳，屏上標(biāo)識EN/OE
unsigned char tab[8];
unsigned char DIS[]={0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15};//行數(shù)據(jù)
/*-----------------------------------------------
16x16漢字取模數(shù)據(jù)
------------------------------------------------*/
unsigned char code hztest[][32]= //二維數(shù)組，目的是減少運(yùn)算，可以用最基本的一維數(shù)組，每個漢字有32個字節(jié)數(shù)據(jù)
{
/*-- 文字: 德 --*/
/*-- 宋體12; 此字體下對應(yīng)的點(diǎn)陣為：寬x高=16x16 --*/
0x08,0x02,0x08,0x02,0xF4,0x7F,0x02,0x02,0xE9,0x3F,0x28,0x25,0x24,0x25,0xE6,0x3F,
0x05,0x00,0xF4,0x7F,0x04,0x02,0x04,0x24,0xA4,0x44,0xA4,0x50,0x94,0x10,0x04,0x1F,
/*-- 文字: 飛 --*/
/*-- 宋體12; 此字體下對應(yīng)的點(diǎn)陣為：寬x高=16x16 --*/
0x00,0x00,0xFF,0x03,0x00,0x02,0x00,0x22,0x00,0x12,0x00,0x0A,0x00,0x06,0x00,0x0A,
0x00,0x12,0x00,0x22,0x00,0x04,0x00,0x04,0x00,0x48,0x00,0x50,0x00,0x60,0x00,0x40,
/*-- 文字: 萊 --*/
/*-- 宋體12; 此字體下對應(yīng)的點(diǎn)陣為：寬x高=16x16 --*/
0x10,0x04,0x10,0x04,0xFF,0x7F,0x90,0x04,0x80,0x00,0xFC,0x1F,0x80,0x00,0x88,0x08,
0x90,0x04,0xFE,0x3F,0xC0,0x01,0xA0,0x02,0x90,0x04,0x8C,0x18,0x83,0x60,0x80,0x00,
};
/*-----------------------------------------------
向595寫入一個字節(jié) 單紅色
------------------------------------------------*/
void InputByte( unsigned char DataR1) //寫一個字節(jié)
{
unsigned char i;
for(i=8; i>0; i--)
{
R1 = !(DataR1&0x01);
T_CLK = 0;
T_CLK = 1;
DataR1 = DataR1 >> 1;
}
}
/*-----------------------------------------------
向595寫入兩個字節(jié) 雙色
------------------------------------------------*/
/*
void Input2Byte( unsigned char DataR1,unsigned char DataG1) //寫一個字節(jié)
{
unsigned char i;
for(i=8; i>0; i--)
{
R1 = !(DataR1&0x01);
G1 = !(DataG1&0x01);
T_CLK = 0;
T_CLK = 1;
DataR1 = DataR1 >> 1;
DataG1 = DataG1 >> 1;
}
}
*/
/*-----------------------------------------------
初始化定時器，做為動態(tài)掃描
------------------------------------------------*/
void Init_Timer1(void)
{
TMOD |= 0x10;
EA=1; //總中斷使能
ET1=1; //定時中斷使能
TR1=1; //打開定時器開關(guān)
}
/*-----------------------------------------------
主程序
------------------------------------------------*/
main()
{
Init_Timer1(); //初始化定時器
while(1)
{
//可以加入其它的控制程序
}
}
/*-----------------------------------------------
定時器執(zhí)行動態(tài)掃描
------------------------------------------------*/
void Timer1_isr(void) interrupt 3
{
static unsigned char count,j;
unsigned char i;
TH1=0xff; //重裝初值
TL1=0;
T_STR=0; //鎖存釋放
for(j=0;j<1;j++) //取每個漢字的前2個字節(jié)，數(shù)據(jù)傳輸完成后鎖存輸出即可 j表示漢字個數(shù)，如果是3個漢字屏就可以修改成3
{
InputByte(~hztest[j][i]);
InputByte(~hztest[j][i+1]);
}
OE=1; //暫時關(guān)閉屏幕，防止出現(xiàn)鬼影，如果沒有使用該引腳控制則會出現(xiàn)拖影現(xiàn)象。
T_STR=1; //鎖存有效，此時一行的數(shù)據(jù)顯示到屏上
P0=DIS[15-count]|0xf0;//用P0口的前4位控制16行，屏內(nèi)部通過4-16譯碼器工作，循環(huán)掃描其他15行
OE=0;//使能
count++;
i+=2; //累加調(diào)用下一行數(shù)據(jù)
if(count==16)
count=0;
if(i==32)
i=0;
}

復(fù)制代碼

ID:453993 · 發(fā)表于 2018-12-25 10:50

Arvin0011 發(fā)表于 2018-12-25 09:16
請說清楚問題，發(fā)照片、程序、電路圖

#include <reg51.h>
unsigned char i;
sbit DATA1=P3^7;
sbit DATA2=P3^5;
sbit CLCK1=P3^6;
sbit CLCK2=P3^4;
#define uchar unsigned char
#define uint unsigned int
void shuru_1();
void shuru_2();
unsigned char num,k,temp1,temp2,zuo=0;
unsigned int timecount;
unsigned char code lie[16]={0x00,0x01,0x02,0x03,0x04,0x05,0x06,0x07,0x08,0x09,0x0a,0x0b,0x0c,0x0d,0x0e,0x0f,};/*74hc154顯示代碼從左到右16列依次選通*/
unsigned char code hang[288]={
0x00,0x00,0x00,0x00,0x1F,0xF8,0x11,0x10,0x11,0x10,0x11,0x10,0x11,0x10,0xFF,0xFE,
0x11,0x11,0x11,0x11,0x11,0x11,0x11,0x11,0x1F,0xF9,0x00,0x01,0x00,0x0F,0x00,0x00,

0x02,0x02,0x0A,0xEA,0xAA,0xAA,0xAA,0xAF,0xAA,0xAA,0xAA,0xEA,0x0A,0x02,0x02,0x00,
0x82,0x4A,0x2A,0x1E,0x0B,0x4A,0x8A,0x7A,0x02,0xFA,0x4B,0x4A,0x4A,0xFA,0x02,0x00,

0x00,0x80,0x60,0xF8,0x07,0x40,0x20,0x18,0x0F,0x08,0xC8,0x08,0x08,0x28,0x18,0x00,
0x01,0x00,0x00,0xFF,0x00,0x10,0x0C,0x03,0x40,0x80,0x7F,0x00,0x01,0x06,0x18,0x00,

0x00,0x00,0x00,0x7F,0x49,0x49,0x49,0x49,0x49,0x49,0x49,0x7F,0x00,0x00,0x00,0x00,
0x81,0x41,0x21,0x1D,0x21,0x41,0x81,0xFF,0x89,0x89,0x89,0x89,0x89,0x81,0x81,0x00,

0x40,0x40,0xC0,0x5F,0x55,0x55,0xD5,0x55,0x55,0x55,0x55,0x5F,0x40,0x40,0x40,0x00,
0x20,0x60,0x3F,0x25,0x15,0x15,0xFF,0x90,0x47,0x29,0x11,0x2D,0x43,0x80,0x80,0x00,

0x10,0x10,0xD0,0xFF,0x90,0x10,0x44,0x54,0xD4,0x74,0x5F,0x54,0xD4,0x54,0x44,0x00,
0x04,0x03,0x00,0xFF,0x00,0x01,0x12,0x11,0x14,0x14,0xFF,0x14,0x14,0x11,0x12,0x00,

0x00,0xF8,0x0C,0x0B,0x08,0x08,0xF8,0x40,0x30,0x8F,0x08,0x08,0x08,0xF8,0x00,0x00,
0x00,0x7F,0x21,0x21,0x21,0x21,0x7F,0x00,0x00,0x00,0x43,0x80,0x40,0x3F,0x00,0x00,

0x10,0x10,0x10,0xFF,0x10,0x10,0xF0,0x00,0x00,0xF8,0x08,0x08,0x08,0xF8,0x00,0x00,
0x80,0x40,0x30,0x0F,0x40,0x80,0x7F,0x00,0x00,0x7F,0x20,0x20,0x20,0x7F,0x00,0x00,

0x10,0x60,0x02,0x8C,0x00,0xF0,0x10,0x10,0x10,0xFF,0x10,0x10,0x10,0xF0,0x00,0x00,
0x04,0x04,0x7E,0x01,0x00,0xFF,0x42,0x42,0x42,0x7F,0x42,0x42,0x42,0xFF,0x00,0x00,

};
void shuru_1()
{uchar t;
for(t=0;t<8;t++)
{
temp1<<=1;
DATA1=CY;
CLCK1=1;
CLCK1=0;
}
}
void shuru_2()
{
uchar t;
for(t=0;t<8;t++)
{
temp2<<=1;
DATA2=CY;
CLCK2=1;
CLCK2=0;
}
}
void main(void)
{
TMOD=0x01;
TH0=(65536-2000)/256;
TL0=(65536-2000)%256;
TR0=1;
ET0=1;
EA=1;
while(1);
}
void serve_led()interrupt 1 using 0
{ k=2;
TH0=(65536-2000)/256;
TL0=(65536-2000)%256;
P2=0xff;
P2 = lie[num];
temp1=hang[num*2+zuo];
shuru_1();
P2 = lie[num];
temp2=hang[zuo+(num*2+1)];
shuru_2();
num++;
if(num==16)
{
num=0;
}
timecount++;
if(timecount==100)
{num=0;
timecount=0;
zuo=zuo+2;
if(zuo==272)
{
zuo=0;
}
}
}

ID:453993 · 發(fā)表于 2018-12-25 11:01

angmall 發(fā)表于 2018-12-25 09:25
程序呢?線路圖呢?什么都沒有,人家想幫你也幫不上呀

我給你來個試試

#include <reg51.h>
unsigned char i;
sbit DATA1=P3^7;
sbit DATA2=P3^5;
sbit CLCK1=P3^6;
sbit CLCK2=P3^4;
#define uchar unsigned char
#define uint unsigned int
void shuru_1();
void shuru_2();
unsigned char num,k,temp1,temp2,zuo=0;
unsigned int timecount;
unsigned char code lie[16]={0x00,0x01,0x02,0x03,0x04,0x05,0x06,0x07,0x08,0x09,0x0a,0x0b,0x0c,0x0d,0x0e,0x0f,};/*74hc154顯示代碼從左到右16列依次選通*/
unsigned char code hang[288]={
0x00,0x00,0x00,0x00,0x1F,0xF8,0x11,0x10,0x11,0x10,0x11,0x10,0x11,0x10,0xFF,0xFE,
0x11,0x11,0x11,0x11,0x11,0x11,0x11,0x11,0x1F,0xF9,0x00,0x01,0x00,0x0F,0x00,0x00,

0x02,0x02,0x0A,0xEA,0xAA,0xAA,0xAA,0xAF,0xAA,0xAA,0xAA,0xEA,0x0A,0x02,0x02,0x00,
0x82,0x4A,0x2A,0x1E,0x0B,0x4A,0x8A,0x7A,0x02,0xFA,0x4B,0x4A,0x4A,0xFA,0x02,0x00,

0x00,0x80,0x60,0xF8,0x07,0x40,0x20,0x18,0x0F,0x08,0xC8,0x08,0x08,0x28,0x18,0x00,
0x01,0x00,0x00,0xFF,0x00,0x10,0x0C,0x03,0x40,0x80,0x7F,0x00,0x01,0x06,0x18,0x00,

0x00,0x00,0x00,0x7F,0x49,0x49,0x49,0x49,0x49,0x49,0x49,0x7F,0x00,0x00,0x00,0x00,
0x81,0x41,0x21,0x1D,0x21,0x41,0x81,0xFF,0x89,0x89,0x89,0x89,0x89,0x81,0x81,0x00,

0x40,0x40,0xC0,0x5F,0x55,0x55,0xD5,0x55,0x55,0x55,0x55,0x5F,0x40,0x40,0x40,0x00,
0x20,0x60,0x3F,0x25,0x15,0x15,0xFF,0x90,0x47,0x29,0x11,0x2D,0x43,0x80,0x80,0x00,

0x10,0x10,0xD0,0xFF,0x90,0x10,0x44,0x54,0xD4,0x74,0x5F,0x54,0xD4,0x54,0x44,0x00,
0x04,0x03,0x00,0xFF,0x00,0x01,0x12,0x11,0x14,0x14,0xFF,0x14,0x14,0x11,0x12,0x00,

0x00,0xF8,0x0C,0x0B,0x08,0x08,0xF8,0x40,0x30,0x8F,0x08,0x08,0x08,0xF8,0x00,0x00,
0x00,0x7F,0x21,0x21,0x21,0x21,0x7F,0x00,0x00,0x00,0x43,0x80,0x40,0x3F,0x00,0x00,

0x10,0x10,0x10,0xFF,0x10,0x10,0xF0,0x00,0x00,0xF8,0x08,0x08,0x08,0xF8,0x00,0x00,
0x80,0x40,0x30,0x0F,0x40,0x80,0x7F,0x00,0x00,0x7F,0x20,0x20,0x20,0x7F,0x00,0x00,

0x10,0x60,0x02,0x8C,0x00,0xF0,0x10,0x10,0x10,0xFF,0x10,0x10,0x10,0xF0,0x00,0x00,
0x04,0x04,0x7E,0x01,0x00,0xFF,0x42,0x42,0x42,0x7F,0x42,0x42,0x42,0xFF,0x00,0x00,

};
void shuru_1()
{uchar t;
for(t=0;t<8;t++)
{
temp1<<=1;
DATA1=CY;
CLCK1=1;
CLCK1=0;
}
}
void shuru_2()
{
uchar t;
for(t=0;t<8;t++)
{
temp2<<=1;
DATA2=CY;
CLCK2=1;
CLCK2=0;
}
}
void main(void)
{
TMOD=0x01;
TH0=(65536-2000)/256;
TL0=(65536-2000)%256;
TR0=1;
ET0=1;
EA=1;
while(1);
}
void serve_led()interrupt 1 using 0
{ k=2;
TH0=(65536-2000)/256;
TL0=(65536-2000)%256;
P2=0xff;
P2 = lie[num];
temp1=hang[num*2+zuo];
shuru_1();
P2 = lie[num];
temp2=hang[zuo+(num*2+1)];
shuru_2();
num++;
if(num==16)
{
num=0;
}
timecount++;
if(timecount==100)
{num=0;
timecount=0;
zuo=zuo+2;
if(zuo==272)
{
zuo=0;
}
}
}

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我自己用8×8連16×16，為什么不能用啊，只有第八行和第16行亮

我自己用8×8連16×16，為什么不能用啊，只有第八行和第16行亮