請問大佬們這個Proteus仿真怎么畫？

ID:828304 · 發(fā)表于 2020-10-17 11:43

#include <reg52.h>

int local(unsigned int i);
unsigned int locals = 0;

sbit ADDR0 = P1^0;
sbit ADDR1 = P1^1;
sbit ADDR2 = P1^2;
sbit ADDR3 = P1^3;
sbit ENLED = P1^4;

sbit key1 = P2^4;
sbit key2 = P2^5;
sbit key3 = P2^6;

unsigned char leds[] = {0xC0,0xF9,0xA4,0xB0,0x99,
0x92,0x82,0xF8,0x80,0x90 };

unsigned char ledss[10][8]={  {0xAA,0x55,0xAA,0x55,0xAA,0x55,0xAA,0x55},
   {0xE7,0xE3,0xE7,0xE7,0xE7,0xE7,0xE7,0xC3},
   {0x81,0x81,0x9F,0x81,0x81,0xF9,0x81,0x81},
      {0x81,0x81,0x9F,0x81,0x81,0x9F,0x81,0x81},
      {0x8F,0x87,0x93,0x99,0x9C,0x00,0x00,0x9F},
   {0x81,0x81,0xF9,0x81,0x81,0x9F,0x81,0x81},
   {0x81,0x81,0xF9,0x81,0x81,0x99,0x81,0x81},
   {0x83,0x83,0x9F,0x9F,0x9F,0x9F,0x9F,0x9F},
   {0x81,0x81,0x99,0x81,0x81,0x99,0x81,0x81},
      {0x81,0x81,0x99,0x81,0x81,0x9F,0x81,0x81}, };

void main()
{
ADDR3 = 0;
ENLED = 0;

EA = 1;
TMOD = 0x01;
ET0 = 1;
TH0 = 0xFC;
TL0 = 0x67;
TR0 = 1;

//開啟九位輸入鍵，其它鍵關(guān)閉
P2 = 0xF1;

while(1)
{
//得到鍵位所在KeyIn1輸入列
if(key1==0)
{
locals = local(1);
TR0 = 1;
}

//得到鍵位所在KeyIn2輸入列
else if(key2==0)
{
locals = local(2);
TR0 = 1;
}

//得到鍵位所在KeyIn3輸入列
else if(key3==0)
{
locals = local(3);
TR0 = 1;
}
}

   //對應(yīng)鍵位賦值數(shù)碼管
}

void InterruptTimer0() interrupt 1
{
static unsigned char i = 0;
TH0 = 0xFC;       // 1ms
TL0 = 0x67;
P0 = 0xFF;
ADDR3 = 0;

switch(i)
{ case 0: ADDR0 = 0;ADDR1 = 0;ADDR2 = 0; P0 = ledss[locals][i];i++;break;
case 1: ADDR0 = 1;ADDR1 = 0;ADDR2 = 0; P0 = ledss[locals][i];i++;break;
case 2: ADDR0 = 0;ADDR1 = 1;ADDR2 = 0; P0 = ledss[locals][i];i++;break;
case 3: ADDR0 = 1;ADDR1 = 1;ADDR2 = 0; P0 = ledss[locals][i];i++;break;
case 4: ADDR0 = 0;ADDR1 = 0;ADDR2 = 1; P0 = ledss[locals][i];i++;break;
case 5: ADDR0 = 1;ADDR1 = 0;ADDR2 = 1; P0 = ledss[locals][i];i++;break;
case 6: ADDR0 = 0;ADDR1 = 1;ADDR2 = 1; P0 = ledss[locals][i];i++;break;
case 7: ADDR0 = 1;ADDR1 = 1;ADDR2 = 1; P0 = ledss[locals][i];i++;break;
case 8: ADDR3 = 1;ADDR0 = 0;ADDR1 = 0;ADDR2 = 0; P0 = leds[locals];i++;break;
case 9: ADDR3 = 1;ADDR0 = 1;ADDR1 = 0;ADDR2 = 1; P0 = leds[locals];i=0;break;
default: break; //代表無此類情況，跳出
}
}

int local(unsigned int i)
{
unsigned int b;
//判斷當(dāng)前鍵位

switch(i)
{
//得到鍵位所在KeyIn1輸入列
case 1: P2 = 0xF7;  //僅僅開啟out1
if(key1 == 0){    b = 1;    }
P2 = 0xFB;  //僅僅開啟out2

if(key1 == 0){    b = 4;    }
P2 = 0xFD;  //僅僅開啟out3

if(key1 == 0){    b = 7;    }
break;

//得到鍵位所在KeyIn2輸入列
case 2: P2 = 0xF7;  //僅僅開啟out1
if(key2 == 0){    b = 2;    }
P2 = 0xFB;  //僅僅開啟out2

if(key2 == 0){    b = 5;    }
P2 = 0xFD;  //僅僅開啟out3

if(key2 == 0){    b = 8;    }
break;

//得到鍵位所在KeyIn3輸入列

case 3: P2 = 0xF7;  //僅僅開啟out1
if(key3 == 0){    b = 3;    }
P2 = 0xFB;  //僅僅開啟out2

if(key3 == 0){    b = 6;       }
P2 = 0xFD;  //僅僅開啟out3

if(key3 == 0){    b = 9;    }
break;

default: break;
}

//重置開啟九位輸入鍵，其它鍵關(guān)閉
P2 = 0xF1;

return b;
}

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請問大佬們這個Proteus仿真怎么畫？

請問大佬們這個Proteus仿真怎么畫？