求大佬幫忙改一下這個程序，通過P3.3口的中斷輸入控制觸發(fā)的角度，然后通過內(nèi)部定時器控制觸發(fā)信號做相應(yīng)的移相然后輸出波形
單片機源程序如下:
#include "reg52.h"
#include"ADC0808.h"
#include "lcd.h"
#define uchar unsigned char
#define uint unsigned int
sbit VT1=P2^0;
sbit VT2=P2^1;
sbit VT3=P2^2;
sbit VT4=P2^3;
sbit VT5=P2^4;
sbit VT6=P2^5;
uchar count;
uchar AD_num,angle_num;//采樣AD的值和導(dǎo)通的角度
uchar AD_signal,achieve_signal;
uint delay_num=0;//延時的時間
void Delay10ms() //@121MHz
{
unsigned char i, j, k;
_nop_();
_nop_();
i = 5;
j = 154;
k = 1;
do
{
do
{
while (--k);
} while (--j);
} while (--i);
}
void SCRTrg(uchar Num) // 脈沖寬度30°
{
switch(Num) // 觸發(fā)相位
{
case 1:
VT1 = 1; // 開通
VT6 = 0;
break;
case 2:
VT1 = 1; // 關(guān)斷
VT6 = 0;
break;
case 3:
VT2 = 0;
VT1 = 1;
break;
case 4:
VT1 = 1;
VT2 = 0;
break;
case 5:
VT3 = 0;
VT2 = 0;
break;
case 6:
VT3 = 0;
VT2 = 0;
break;
case 7:
VT3 = 0;
VT4 = 0;
break;
case 8:
VT3 = 0;
VT4 = 0;
break;
case 9:
VT5 = 1;
VT4 = 1;
break;
case 10:
VT5 = 0;
VT4 = 0;
break;
case 11:
VT5 = 0;
VT6 = 0;
break;
case 12:
VT5 = 0;
VT6 = 0;
break;
default:
break;
}
}
//定時器和外部中斷初始化
void Timer_Init(void)
{
TMOD=0x11;
TH1=0xF9;
TL1= 0x7F;
ET0=1;
ET1=1;
IT0 = 1; // 下降沿觸發(fā)
PX0=1;//外部中斷0定義為高優(yōu)先級
EX0=1;
}
void main(void)
{
Timer_Init();
VT1=0;
/*VT2=0;
VT3=0;
VT4=0;
VT5=0;
VT6=0;*/
LcdInit();
AD_num=ADCInit();
angle_num=(uint)((255-AD_num)/255.0*180);
delay_num=(uint)(angle_num*10000/180.0);
LcdPrintf(0,"angle:");
LcdDisplayI(6,angle_num);
EA=1;
while(1)
{
if(AD_signal==1)
{
AD_signal=0;
if(AD_num!=ADCInit())
{
TR0=0;
TR1=0;
AD_num=ADCInit();
angle_num=(uint)((255-AD_num)/255.0*180);
delay_num=(uint)(angle_num*10000/180.0);
LcdDisplayI(6,angle_num);
achieve_signal=1;
EX0=1;
}
}
}
}
void exint0() interrupt 0
{
Delay10ms();
count=1;
if(angle_num<60)
count=1;
else if(angle_num<120)
count=11;
else
count=9;
TH0=(65536-delay_num)/256;
TL0=(65536-delay_num)%256;
TR0=1;
EX0=0;//關(guān)外部中斷
}
void Time0Int() interrupt 1
{
TH0=(65536-delay_num)/256;
TL0=(65536-delay_num)%256;
TH1=0xF9;
TL1= 0x82;
TR0=0;
TR1=1;
}
void Time1Int() interrupt 3
{
TH1=0xF9;
TL1= 0x82;
SCRTrg(count++);
if(count==6)
AD_signal=1;
if(count>12)
{
count=1;
}
}
|
50 黑幣
