我想做個簡易的計算器，999以內(nèi)加減乘除，數(shù)碼管顯示，但是鍵盤的檢測有問題，請問如何讓矩陣鍵盤掃描多個數(shù)字呢，一下是程序。
#include<reg52.h>
#define uint unsigned int
#define uchar unsigned char
sbit dula=P2^6;
sbit wela=P2^7;
sbit key1=P3^4;
uchar code table[]={0x3f,0x06,0x5b,0x4f,
0x66,0x6d,0x7d,0x07,
0x7f,0x6f,0x77,0x7c,
0x39,0x5e,0x79,0x71,0};
uchar num,temp,shuzi1bai,shuzi1shi,shuzi1ge,shuzi2bai,shuzi2shi,shuzi2ge,jihao1,wan,qian,bai,shi,ge,fuhao,shuzi1,shuzi2;
long jieguo;
void delay (uint);
void display2(uchar,uchar);
//void display3(uchar,uchar,uchar);
//void display1(uchar,uchar,uchar,uchar,uchar);
uchar keyscan();
//uchar keyscan2();
void display(uchar );
//uint fuhao();
void main()
{
uchar i=1;
num=16;
dula=1;
P0=0;
dula=0;
wela=1;
P0=0xdf;
wela=0;
while(1)
{
keyscan();
if(num<=9&&num>=0&&i==1)
{
shuzi1bai=num;
display(shuzi1bai);
i++;
}
keyscan();
if(num<=9&&num>=0&&i==2)
{
shuzi1shi=num;
display(shuzi1shi);
i++;
}
keyscan();
if(num<=9&&num>=0&&i==3)
{
shuzi1ge=num;
display3(shuzi1bai/100,shuzi1shi/10,shuzi1ge);
shuzi1=shuzi1bai*100+shuzi1shi*10+shuzi1ge;
i++;
}
*******************中間這一段暫時不看**********************************
keyscan();
if(num>=10&&num<=13&&i==2)
{
shuzi1shi=num;
display(shuzi1shi);
i++;
}
keyscan();
if(num<=9&&num>=0&&i==3)
{
shuzi1ge=num;
display(shuzi1ge);
i++;
}
keyscan();
if(num==14&&i==4)
{
jihao1=1;
if(shuzi1>=0&&shuzi2>=0&&fuhao>=0)
{
if(fuhao==10&&jihao1==1)
{
jieguo=shuzi1+shuzi2;
}
if(fuhao==11&&jihao1==1)
{
jieguo=shuzi1-shuzi2;
}
if(fuhao==12&&jihao1==1)
{
jieguo=shuzi1*shuzi2;
}
if(fuhao==13&&jihao1==1)
{
jieguo=shuzi1/shuzi2;
}
if(jieguo<=9)
display(jieguo);
else
{
shi=jieguo/10;
ge=jieguo%10;
display2(shi,ge);
}
}
} */
while(shuzi1>=0&&shuzi2>=0&&fuhao>=0)
EA=1;
//delay(20);
keyscan();
if(num<=9&&num>=0&&i==2)
{
shuzi2=num;
display(shuzi2);
i++;
}
delay(20);
keyscan();
if(num>=12&&num<=15&&i==3)
{
i=1;
}
}
}
********************************************************************
void display(uchar aa)
{
dula=1;
P0=table[aa];
dula=0;
}
uchar keyscan()
{
P3=0xfe;
temp=P3;
temp=temp&0xf0;
while(temp!=0xf0)
{
delay(5);
temp=P3;
temp=temp&0xf0;
while(temp!=0xf0)
{
temp=P3;
switch(temp)
{
case 0xee:num=0;
break;
case 0xde:num=1;
break;
case 0xbe:num=2;
break;
case 0x7e:num=3;
break;
}
while(temp!=0xf0)
{
temp=P3;
temp=temp&0xf0;
}
}
}
P3=0xfd;
temp=P3;
temp=temp&0xf0;
while(temp!=0xf0)
{
delay(5);
temp=P3;
temp=temp&0xf0;
while(temp!=0xf0)
{
temp=P3;
switch(temp)
{
case 0xed:num=4;
break;
case 0xdd:num=5;
break;
case 0xbd:num=6;
break;
case 0x7d:num=7;
break;
}
while(temp!=0xf0)
{
temp=P3;
temp=temp&0xf0;
}
}
}
P3=0xfb;
temp=P3;
temp=temp&0xf0;
while(temp!=0xf0)
{
delay(5);
temp=P3;
temp=temp&0xf0;
while(temp!=0xf0)
{
temp=P3;
switch(temp)
{
case 0xeb:num=8;
break;
case 0xdb:num=9;
break;
case 0xbb:num=10;
break;
case 0x7b:num=11;
break;
}
while(temp!=0xf0)
{
temp=P3;
temp=temp&0xf0;
}
}
}
P3=0xf7;
temp=P3;
temp=temp&0xf0;
while(temp!=0xf0)
{
delay(5);
temp=P3;
temp=temp&0xf0;
while(temp!=0xf0)
{
temp=P3;
switch(temp)
{
case 0xe7:num=12;
break;
case 0xd7:num=13;
break;
case 0xb7:num=14;
break;
case 0x77:num=15;
break;
}
while(temp!=0xf0)
{
temp=P3;
temp=temp&0xf0;
}
}
}
return num;
}
void delay(uint z)
{
uint x,y;
for(x=z;x>0;x--)
for(y=110;y>0;y--);
}
void display1(uchar wan,uchar qian,uchar bai,uchar shi,uchar ge)
{
dula=1;
P0=table[wan];
dula=0;
P0=0xff;
wela=1;
P0=0xfd;
wela=0;
delay(1);
dula=1;
P0=table[qian];
dula=0;
P0=0xff;
wela=1;
P0=0xfb;
wela=0;
delay(1);
dula=1;
P0=table[bai];
dula=0;
P0=0xff;
wela=1;
P0=0xf7;
wela=0;
delay(1);
dula=1;
P0=table[shi];
dula=0;
P0=0xff;
wela=1;
P0=0xef;
wela=0;
delay(1);
dula=1;
P0=table[ge];
dula=0;
P0=0xff;
wela=1;
P0=0xdf;
wela=0;
delay(1);
}
void display2(uchar shi,uchar ge)
{
dula=1;
P0=table[shi];
dula=0;
P0=0xff;
wela=1;
P0=0xef;
wela=0;
delay(1);
dula=1;
P0=table[ge];
dula=0;
P0=0xff;
wela=1;
P0=0xdf;
wela=0;
delay(1);
}
void display3(uchar bai,uchar shi,uchar ge)
{
dula=1;
P0=table[bai];
dula=0;
P0=0xff;
wela=1;
P0=0xf7;
wela=0;
delay(1);
dula=1;
P0=table[shi];
dula=0;
P0=0xff;
wela=1;
P0=0xef;
wela=0;
delay(1);
dula=1;
P0=table[ge];
dula=0;
P0=0xff;
wela=1;
P0=0xdf;
wela=0;
delay(1);
}
按下第二個鍵時還是顯示的第一個數(shù)，求解。。。。
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