新人求大佬幫幫(C語言程序問題) 液晶屏幕無法正確顯示想要的數(shù)字

ID:1041179 · 發(fā)表于 2022-8-2 08:55

#include<STC8xxxx.h>
#include <stdio.h>
#include "intrins.h"
/*************  外部函數(shù)和變量聲明 *****************/
#define  uint unsigned int
#define  uchar  unsigned char
uchar  ScanCoun,ZZ;
#define MAIN_Fosc 22118400L //定義主時鐘

//COM  SEG 的管腳定義
sbit  LED=P1^6;  //LED
sbit COM0=P1^0;  //COM0
sbit COM1=P1^1;  //COM1
sbit COM2=P1^2;  //COM2
sbit COM3=P1^3;  //COM3
sbit SEG0=P1^4;  //SEG0
sbit SEG1=P1^5;  //SEG1
sbit SEG2=P2^6;  //SEG2
sbit SEG3=P2^5;  //SEG3
sbit SEG4=P2^4;  //SEG4
sbit SEG5=P2^3;  //SEG5
sbit SEG6=P2^2;  //SEG6
sbit SEG7=P2^1;  //SEG7
sbit SEG8=P2^0;  //SEG8
uchar ScanCoun=0;                //動態(tài)掃描顯示位數(shù)計數(shù)器
uchar *Tdat1,*Tdat2;
uchar LCD_load,W0,bai,shi,ge,W4;
//0～9的段碼查詢表
uchar code seg_code[12]={0xFA,0x60,0xD2,0xF4,0x6C,0xBC,0xBE,0x0E,0xEF,0xFC,0x01};
                        //0 1 2 3 4 5 6 7 8 9 Dot
////段碼緩沖區(qū)
uchar SegBuf[8]={0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00};//COM1、COM2、COM3、COM4對應(yīng)的段碼緩沖
/////////////延時 ms//////////////
void DelayMS(uint ms)
{
uchar i,j;
for(i=0; i<250; i++)
for(j=0; j<200;j++);
}
//COM口設(shè)置高阻態(tài)
void IO_set()
{
P1n_open_drain(1<<3);//P1^3高阻 COM3
P1n_open_drain(1<<2);//P1^2高阻 COM2
P1n_open_drain(1<<1);//P1^1高阻 COM1
P1n_open_drain(1<<0);//P1^0高阻 COM0

P2M1=0x00;  //P2口為輸出
P2M0=0xFF;                //SEG2--SEG8
P1n_push_pull(1<<4);//P1^4輸出 SEG0
P1n_push_pull(1<<5);//P1^5輸出 SEG1
P1n_push_pull(1<<6);//P1^6輸出 LED
}

void xianshi()
{
LCD_load=111;
bai=LCD_load/100%10;
shi=LCD_load/10%10;
ge=LCD_load%10;
}
//seg定義
void Seg2Seg()
{
uchar SegXX;
SegBuf[0]=0x00;SegBuf[1]=0x00; //一定要設(shè)置為0,輸出緩存初始化
SegBuf[2]=0x00;SegBuf[3]=0x00;
SegBuf[4]=0x00;SegBuf[5]=0x00;
SegBuf[6]=0x00;SegBuf[7]=0x00;
//把3位數(shù)字的SEG放到COM1、COM2、COM3、COM4對應(yīng)的SEGBUF[]里面
//LCD的管腳定義與LED不同，不是一個COM對應(yīng)一位數(shù)字，而是對應(yīng)每個數(shù)字的一部分SEG
// 1 2 3 4 5 6 7 8 9 10  11  12             | 13
//COM0             T5  T4  1F  1A  2F  2a  3f  3a -- segBuf【0】| v -- segBuf【4】
//---- COM1          T6  T3  1G  1B  2G  2b  3g  3b -- segBuf【1】| A -- segBuf【5】
//-------- COM2    T7  T2  1E  1C  2E  2c  3e  3c -- segBuf【2】| H -- segBuf【6】
//-------- ---- COM3  T8  T1 /  1D  P1  2d  P2  3d -- segBuf【3】| % -- segBuf【7】

// SegXX=seg_code[W0];  //電池方格
// if (SegXX&0x80) SegBuf[0]|=0x10; //T4
// if (SegXX&0x40) SegBuf[1]|=0x10; //T3
// if (SegXX&0x20) SegBuf[2]|=0x10; //T2
// if (SegXX&0x10) SegBuf[3]|=0x10; //T1
// if (SegXX&0x08) SegBuf[0]|=0x20; //T5
// if (SegXX&0x04) SegBuf[1]|=0x20; //T6
// if (SegXX&0x02) SegBuf[2]|=0x20; //T7
// if (SegXX&0x01) SegBuf[3]|=0x20; //T8

SegXX=seg_code[bai];  //第1位數(shù)字
if (SegXX&0x80) SegBuf[0]|=0x20; //1a
if (SegXX&0x40) SegBuf[1]|=0x20; //1b
if (SegXX&0x20) SegBuf[2]|=0x20; //1c
if (SegXX&0x10) SegBuf[3]|=0x20; //1d

if (SegXX&0x08) SegBuf[0]|=0x40; //1f
if (SegXX&0x04) SegBuf[1]|=0x40; //1g
if (SegXX&0x02) SegBuf[2]|=0x40; //1e
// if (SegXX&0x01) SegBuf[3]|=0x40; //0

SegXX=(seg_code[ge]|0x01); //第2位數(shù)字
if (SegXX&0x80) SegBuf[0]|=0x08;//2a
if (SegXX&0x40) SegBuf[1]|=0x08;//2b
if (SegXX&0x20) SegBuf[2]|=0x08;//2c
if (SegXX&0x10) SegBuf[3]|=0x08;//2d
if (SegXX&0x08) SegBuf[0]|=0x10;//2f
if (SegXX&0x04) SegBuf[1]|=0x10;//2g
if (SegXX&0x02) SegBuf[2]|=0x10;//2e
if (SegXX&0x01) SegBuf[3]|=0x10;//p1

SegXX=seg_code[shi]; //第3位數(shù)字
if (SegXX&0x80) SegBuf[0]|=0x02;//3a
if (SegXX&0x40) SegBuf[1]|=0x02;//3b
if (SegXX&0x20) SegBuf[2]|=0x02;//3c
if (SegXX&0x10) SegBuf[3]|=0x02;//3d
if (SegXX&0x08) SegBuf[0]|=0x04;//3f
if (SegXX&0x04) SegBuf[1]|=0x04;//3g
if (SegXX&0x02) SegBuf[2]|=0x04;//3e
if (SegXX&0x01) SegBuf[3]|=0x04;//p2

//SegXX=(seg_code[W4]|0x01);  //符號顯示
// if (SegXX&0x80) SegBuf[4]|=0x01; //v
// if (SegXX&0x40) SegBuf[5]|=0x01; //a
// if (SegXX&0x20) SegBuf[6]|=0x01; //h
// if (SegXX&0x10) SegBuf[7]|=0x01; //&
}
/*******************************************
/////////////定時器初始化////////////
********************************************/
void InitInterResource()
{
IE=0;    //關(guān)全部中斷
TCON=0;    //清全部中斷請求
IP=0;    //清中斷優(yōu)先級
TMOD=0x01;  //T0工作方式1（16位定時器）
TH0=0xEC; //T0定時器輔初值
TL0=0x78;
TR0=1;    //允許T0定時
ET0=1;    //允許T0中斷
EA=0;    //關(guān)全局中斷
}

void main()
{
   DelayMS(20);
   IO_set();
   InitInterResource();
   EA=1;       //開全局中斷
   while(1);
}

void tmr0_p(void) interrupt 1
{
Seg2Seg();
switch(ScanCoun)             //動態(tài)掃描顯示
{
   case 0:                      //COM0正向驅(qū)動
*Tdat1=SegBuf[0];
SEG0 = (bit)(*Tdat1&0x01);
SEG1 = (bit)(*Tdat1&0x02);
SEG2 = (bit)(*Tdat1&0x04);
SEG3 = (bit)(*Tdat1&0x08);
SEG4 = (bit)(*Tdat1&0x10);
SEG5 = (bit)(*Tdat1&0x20);
SEG6 = (bit)(*Tdat1&0x40);
SEG7 = (bit)(*Tdat1&0x80);
*Tdat2=SegBuf[4];
SEG8 = (bit)(*Tdat2&0x01);
COM0=0;
   P1n_push_pull(1<<1);//P1^1輸出  COM1
   P1n_open_drain(1<<2);//P1^2高阻 COM3
   P1n_open_drain(1<<3);//P1^3高阻 COM2
   P1n_open_drain(1<<0);//P1^0高阻 COM0
      break;

   case 1:                      //COM0反向驅(qū)動
   *Tdat1=~SegBuf[0];
   SEG0 = (bit)(*Tdat1&0x01);
   SEG1 = (bit)(*Tdat1&0x02);
   SEG2 = (bit)(*Tdat1&0x04);
   SEG3 = (bit)(*Tdat1&0x08);
   SEG4 = (bit)(*Tdat1&0x10);
   SEG5 = (bit)(*Tdat1&0x20);
   SEG6 = (bit)(*Tdat1&0x40);
   SEG7 = (bit)(*Tdat1&0x80);
   *Tdat2=~SegBuf[4];
   SEG8 = (bit)(*Tdat2&0x01);
   COM0=1;
   P1n_push_pull(1<<1);//P1^1輸出  COM1
   P1n_open_drain(1<<2);//P1^2高阻 COM3
   P1n_open_drain(1<<3);//P1^3高阻 COM2
   P1n_open_drain(1<<0);//P1^0高阻 COM0
      break;

   case 2:                      //COM1正向驅(qū)動
   *Tdat1=SegBuf[1];
   SEG0 = (bit)(*Tdat1&0x01);
   SEG1 = (bit)(*Tdat1&0x02);
   SEG2 = (bit)(*Tdat1&0x04);
   SEG3 = (bit)(*Tdat1&0x08);
   SEG4 = (bit)(*Tdat1&0x10);
   SEG5 = (bit)(*Tdat1&0x20);
   SEG6 = (bit)(*Tdat1&0x40);
   SEG7 = (bit)(*Tdat1&0x80);
   *Tdat2=SegBuf[5];
   SEG8 = (bit)(*Tdat2&0x01);
   COM1=0;
   P1n_push_pull(1<<1);//P1^1輸出  COM1
   P1n_open_drain(1<<2);//P1^2高阻 COM3
   P1n_open_drain(1<<3);//P1^3高阻 COM2
   P1n_open_drain(1<<0);//P1^0高阻 COM0
      break;

   case 3:                      //COM1反向驅(qū)動
   *Tdat1=~SegBuf[1];
   SEG0 = (bit)(*Tdat1&0x01);
   SEG1 = (bit)(*Tdat1&0x02);
   SEG2 = (bit)(*Tdat1&0x04);
   SEG3 = (bit)(*Tdat1&0x08);
   SEG4 = (bit)(*Tdat1&0x10);
   SEG5 = (bit)(*Tdat1&0x20);
   SEG6 = (bit)(*Tdat1&0x40);
   SEG7 = (bit)(*Tdat1&0x80);
   *Tdat2=~SegBuf[5];
   SEG8 = (bit)(*Tdat2&0x01);
   COM1=1;
   P1n_push_pull(1<<1);//P1^1輸出  COM1
   P1n_open_drain(1<<2);//P1^2高阻 COM3
   P1n_open_drain(1<<3);//P1^3高阻 COM2
   P1n_open_drain(1<<0);//P1^0高阻 COM0
      break;

   case 4:                      //COM2正向驅(qū)動
   *Tdat1=SegBuf[2];
   SEG0 = (bit)(*Tdat1&0x01);
SEG1 = (bit)(*Tdat1&0x02);
SEG2 = (bit)(*Tdat1&0x04);
SEG3 = (bit)(*Tdat1&0x08);
SEG4 = (bit)(*Tdat1&0x10);
SEG5 = (bit)(*Tdat1&0x20);
SEG6 = (bit)(*Tdat1&0x40);
SEG7 = (bit)(*Tdat1&0x80);
*Tdat2=SegBuf[6];
SEG8 = (bit)(*Tdat2&0x01);
COM2=0;
   P1n_push_pull(1<<1);//P1^1輸出  COM1
   P1n_open_drain(1<<2);//P1^2高阻 COM3
   P1n_open_drain(1<<3);//P1^3高阻 COM2
   P1n_open_drain(1<<0);//P1^0高阻 COM0
      break;

   case 5:                      //COM2反向驅(qū)動
      *Tdat1=~SegBuf[2];
SEG0 = (bit)(*Tdat1&0x01);
SEG1 = (bit)(*Tdat1&0x02);
SEG2 = (bit)(*Tdat1&0x04);
SEG3 = (bit)(*Tdat1&0x08);
   SEG4 = (bit)(*Tdat1&0x10);
SEG5 = (bit)(*Tdat1&0x20);
SEG6 = (bit)(*Tdat1&0x40);
SEG7 = (bit)(*Tdat1&0x80);
*Tdat2=~SegBuf[6];
SEG8 = (bit)(*Tdat2&0x01);
COM2=1;
   P1n_push_pull(1<<1);//P1^1輸出  COM1
   P1n_open_drain(1<<2);//P1^2高阻 COM3
   P1n_open_drain(1<<3);//P1^3高阻 COM2
   P1n_open_drain(1<<0);//P1^0高阻 COM0
      break;

   case 6:                      //COM3正向驅(qū)動
   *Tdat1=SegBuf[3];
   SEG0 = (bit)(*Tdat1&0x01);
   SEG1 = (bit)(*Tdat1&0x02);
   SEG2 = (bit)(*Tdat1&0x04);
   SEG3 = (bit)(*Tdat1&0x08);
   SEG4 = (bit)(*Tdat1&0x10);
   SEG5 = (bit)(*Tdat1&0x20);
   SEG6 = (bit)(*Tdat1&0x40);
   SEG7 = (bit)(*Tdat1&0x80);
   *Tdat2=SegBuf[7];
   SEG8 = (bit)(*Tdat2&0x01);
   COM3=0;
   P1n_push_pull(1<<1);//P1^1輸出  COM1
   P1n_open_drain(1<<2);//P1^2高阻 COM3
   P1n_open_drain(1<<3);//P1^3高阻 COM2
   P1n_open_drain(1<<0);//P1^0高阻 COM0
      break;

   case 7:                      //COM3反向驅(qū)動
   *Tdat1=~SegBuf[3];
   SEG0 = (bit)(*Tdat1&0x01);
   SEG1 = (bit)(*Tdat1&0x02);
   SEG2 = (bit)(*Tdat1&0x04);
   SEG3 = (bit)(*Tdat1&0x08);
   SEG4 = (bit)(*Tdat1&0x10);
   SEG5 = (bit)(*Tdat1&0x20);
   SEG6 = (bit)(*Tdat1&0x40);
   SEG7 = (bit)(*Tdat1&0x80);
   *Tdat2=~SegBuf[7];
   SEG8 = (bit)(*Tdat2&0x01);
   COM3=1;
   P1n_push_pull(1<<1);//P1^1輸出  COM1
   P1n_open_drain(1<<2);//P1^2高阻 COM3
   P1n_open_drain(1<<3);//P1^3高阻 COM2
   P1n_open_drain(1<<0);//P1^0高阻 COM0
      break;
   }

   ScanCoun++;    //下一位
   if(ScanCoun>7)
   ScanCoun=0;

   TL0=0x78;    //重新定時5ms
   TH0=0xec;
   ZZ++;
   EA=1;
  }

//5V供電單片機引腳直接驅(qū)動LCD屏幕（1/4BUTY,1/3BIAS）,編譯無錯，就是沒有搞懂那里出問題了，一直沒有顯示正確的數(shù)

ID:1041179 · 發(fā)表于 2022-8-2 10:23

////////////動態(tài)掃描函數(shù)////////////
void tmr0_p(void) interrupt 1
{
Seg2Seg();
switch(ScanCoun)             //動態(tài)掃描顯示
{
   case 0:                      //COM0正向驅(qū)動
      *Tdat1=SegBuf[0];
SEG0 = (bit)(*Tdat1&0x01);
SEG1 = (bit)(*Tdat1&0x02);
SEG2 = (bit)(*Tdat1&0x04);
SEG3 = (bit)(*Tdat1&0x08);
SEG4 = (bit)(*Tdat1&0x10);
SEG5 = (bit)(*Tdat1&0x20);
SEG6 = (bit)(*Tdat1&0x40);
SEG7 = (bit)(*Tdat1&0x80);
      *Tdat2=SegBuf[4];
SEG8 = (bit)(*Tdat2&0x01);
COM0=0;
//    P1n_push_pull(1<<0);//P1^0輸出  COM0
   P1n_open_drain(1<<3);//P1^3高阻 COM2
   P1n_open_drain(1<<2);//P1^2高阻 COM3
               P1n_open_drain(1<<1);//P1^1高阻 COM1
      break;

   case 1:                      //COM0反向驅(qū)動
*Tdat1=~SegBuf[0];
               SEG0 = (bit)(*Tdat1&0x01);
   SEG1 = (bit)(*Tdat1&0x02);
   SEG2 = (bit)(*Tdat1&0x04);
   SEG3 = (bit)(*Tdat1&0x08);
            SEG4 = (bit)(*Tdat1&0x10);
   SEG5 = (bit)(*Tdat1&0x20);
   SEG6 = (bit)(*Tdat1&0x40);
   SEG7 = (bit)(*Tdat1&0x80);
   *Tdat2=~SegBuf[4];
   SEG8 = (bit)(*Tdat2&0x01);
   COM0=1;
         // P1n_push_pull(1<<0);//P1^0輸出  COM0
   P1n_open_drain(1<<3);//P1^3高阻 COM3
   P1n_open_drain(1<<2);//P1^2高阻 COM2
               P1n_open_drain(1<<1);//P1^1高阻 COM1
      break;

   case 2:                      //COM1正向驅(qū)動
   *Tdat1=SegBuf[1];
               SEG0 = (bit)(*Tdat1&0x01);
   SEG1 = (bit)(*Tdat1&0x02);
   SEG2 = (bit)(*Tdat1&0x04);
   SEG3 = (bit)(*Tdat1&0x08);
               SEG4 = (bit)(*Tdat1&0x10);
   SEG5 = (bit)(*Tdat1&0x20);
   SEG6 = (bit)(*Tdat1&0x40);
   SEG7 = (bit)(*Tdat1&0x80);
   *Tdat2=SegBuf[5];
               SEG8 = (bit)(*Tdat2&0x01);
   COM1=0;
         //  P1n_push_pull(1<<1);//P1^1輸出  COM1
   P1n_open_drain(1<<3);//P1^3高阻 COM3
   P1n_open_drain(1<<2);//P1^2高阻 COM2
            P1n_open_drain(1<<0);//P1^0高阻 COM0
      break;

   case 3:                      //COM1反向驅(qū)動
   *Tdat1=~SegBuf[1];
            SEG0 = (bit)(*Tdat1&0x01);
   SEG1 = (bit)(*Tdat1&0x02);
   SEG2 = (bit)(*Tdat1&0x04);
   SEG3 = (bit)(*Tdat1&0x08);
               SEG4 = (bit)(*Tdat1&0x10);
   SEG5 = (bit)(*Tdat1&0x20);
   SEG6 = (bit)(*Tdat1&0x40);
   SEG7 = (bit)(*Tdat1&0x80);
   *Tdat2=~SegBuf[5];
   SEG8 = (bit)(*Tdat2&0x01);
   COM1=1;
         // P1n_push_pull(1<<1);//P1^1輸出  COM1
   P1n_open_drain(1<<3);//P1^3高阻 COM3
   P1n_open_drain(1<<2);//P1^2高阻 COM2
               P1n_open_drain(1<<0);//P1^0高阻 COM0
      break;

   case 4:                      //COM2正向驅(qū)動
   *Tdat1=SegBuf[2];
                     SEG0 = (bit)(*Tdat1&0x01);
SEG1 = (bit)(*Tdat1&0x02);
SEG2 = (bit)(*Tdat1&0x04);
SEG3 = (bit)(*Tdat1&0x08);
SEG4 = (bit)(*Tdat1&0x10);
SEG5 = (bit)(*Tdat1&0x20);
SEG6 = (bit)(*Tdat1&0x40);
SEG7 = (bit)(*Tdat1&0x80);
*Tdat2=SegBuf[6];
SEG8 = (bit)(*Tdat2&0x01);
COM2=0;
// P1n_push_pull(1<<2);//P1^2輸出  COM2
   P1n_open_drain(1<<3);//P1^3高阻 COM3
   P1n_open_drain(1<<1);//P1^1高阻 COM1
               P1n_open_drain(1<<0);//P1^0高阻 COM0
      break;

   case 5:                      //COM2反向驅(qū)動
      *Tdat1=~SegBuf[2];
SEG0 = (bit)(*Tdat1&0x01);
SEG1 = (bit)(*Tdat1&0x02);
SEG2 = (bit)(*Tdat1&0x04);
SEG3 = (bit)(*Tdat1&0x08);
                     SEG4 = (bit)(*Tdat1&0x10);
SEG5 = (bit)(*Tdat1&0x20);
SEG6 = (bit)(*Tdat1&0x40);
SEG7 = (bit)(*Tdat1&0x80);
*Tdat2=~SegBuf[6];
SEG8 = (bit)(*Tdat2&0x01);
COM2=1;
// P1n_push_pull(1<<2);//P1^2輸出  COM2
   P1n_open_drain(1<<3);//P1^3高阻 COM3
   P1n_open_drain(1<<1);//P1^1高阻 COM1
               P1n_open_drain(1<<0);//P1^0高阻 COM0
      break;

   case 6:                      //COM3正向驅(qū)動
   *Tdat1=SegBuf[3];
               SEG0 = (bit)(*Tdat1&0x01);
   SEG1 = (bit)(*Tdat1&0x02);
   SEG2 = (bit)(*Tdat1&0x04);
   SEG3 = (bit)(*Tdat1&0x08);
               SEG4 = (bit)(*Tdat1&0x10);
   SEG5 = (bit)(*Tdat1&0x20);
   SEG6 = (bit)(*Tdat1&0x40);
   SEG7 = (bit)(*Tdat1&0x80);
*Tdat2=SegBuf[7];
   SEG8 = (bit)(*Tdat2&0x01);
   COM3=0;
// P1n_push_pull(1<<3);//P1^3輸出  COM3
   P1n_open_drain(1<<2);//P1^2高阻 COM2
   P1n_open_drain(1<<1);//P1^1高阻 COM1
               P1n_open_drain(1<<0);//P1^0高阻 COM0
      break;

   case 7:                      //COM3反向驅(qū)動
   *Tdat1=~SegBuf[3];
               SEG0 = (bit)(*Tdat1&0x01);
   SEG1 = (bit)(*Tdat1&0x02);
   SEG2 = (bit)(*Tdat1&0x04);
   SEG3 = (bit)(*Tdat1&0x08);
               SEG4 = (bit)(*Tdat1&0x10);
   SEG5 = (bit)(*Tdat1&0x20);
   SEG6 = (bit)(*Tdat1&0x40);
   SEG7 = (bit)(*Tdat1&0x80);
   *Tdat2=~SegBuf[7];
   SEG8 = (bit)(*Tdat2&0x01);
   COM3=1;
// P1n_push_pull(1<<3);//P1^3輸出  COM3
   P1n_open_drain(1<<2);//P1^2高阻 COM2
   P1n_open_drain(1<<1);//P1^1高阻 COM1
            P1n_open_drain(1<<0);//P1^0高阻 COM0
      break;
   }

   ScanCoun++;    //下一位
   if(ScanCoun>7)
   ScanCoun=0;

   TL0=0x78;    //重新定時5ms
   TH0=0xec;
   ZZ++;
   EA=1;
  }

什么代碼這部分復(fù)制錯了

全是P1^1輸出了，但是改完也還是顯示一樣的東西

好奇怪

ID:1023753 · 發(fā)表于 2022-8-2 13:40

先驅(qū)動一位顯示，成功了在擴展

ID:123289 · 發(fā)表于 2022-8-2 15:35

教你一個方法。
1、先顯示一個段，看看亮在何處。
2、再顯示另一個段，看兩者的位置關(guān)系。
3、逐漸增到7個段，你就可以拼成0-9了。

ID:1041179 · 發(fā)表于 2022-8-2 15:48

haiyang201 發(fā)表于 2022-8-2 13:40
先驅(qū)動一位顯示，成功了在擴展

好，多謝

ID:1041179 · 發(fā)表于 2022-8-2 15:48

yzwzfyz 發(fā)表于 2022-8-2 15:35
教你一個方法。
1、先顯示一個段，看看亮在何處。
2、再顯示另一個段，看兩者的位置關(guān)系。

好，我去試試

ID:723681 · 發(fā)表于 2022-8-2 15:52

1.先檢測引腳是否連接正確
2.硬件正確調(diào)用基本的驅(qū)動函數(shù) 顯示一小段
3.成功顯示一段再嘗試顯示數(shù)字

ID:844772 · 發(fā)表于 2022-8-2 21:25

太長了看不下去，又沒什么難度，你能不能發(fā)一下，應(yīng)該顯示什么字，實際顯示的什么。

ID:401564 · 發(fā)表于 2022-8-2 22:13

新人不是應(yīng)該先寫個延時,跑馬燈什么的嗎?
你duang duang一堆那么長的代碼上來,誰能找到問題?別人手上都不一定有你用的單片機型號,也不一定有你手頭上的顯示屏
正確的做法是先寫一個單純的函數(shù),只顯示一個數(shù)字3之類的,只要能顯示一個數(shù)字了,再改另外一個數(shù)字燒錄看一下
只要能顯示一個數(shù)字了,其它功能就慢慢的增加,每增加一個功能就燒錄驗證一次
而不是像你現(xiàn)在這樣,要么是自己先按著自己的想法,一下子把所有的功能都寫完
又或者是直接復(fù)制別人的代碼,這改一下,那改一下
然后一燒錄,才發(fā)現(xiàn)不是你想要的效果

ID:1041179 · 發(fā)表于 2022-8-4 09:41

Y_G_G 發(fā)表于 2022-8-2 22:13
新人不是應(yīng)該先寫個延時,跑馬燈什么的嗎?
你duang duang一堆那么長的代碼上來,誰能找到問題?別人手上都不 ...

多謝回復(fù)，第一次發(fā)帖不太會，謝謝指點，以后注意嘿嘿嘿

ID:1041179 · 發(fā)表于 2022-8-4 09:42

Youth8023 發(fā)表于 2022-8-2 15:52
1.先檢測引腳是否連接正確
2.硬件正確調(diào)用基本的驅(qū)動函數(shù) 顯示一小段
3.成功顯示一段再嘗試顯示數(shù)字

多謝多謝，問題已經(jīng)解決就是引腳連接問題

ID:1041179 · 發(fā)表于 2022-8-4 09:43

glinfei 發(fā)表于 2022-8-2 21:25
太長了看不下去，又沒什么難度，你能不能發(fā)一下，應(yīng)該顯示什么字，實際顯示的什么。

多謝幫助回復(fù)，問題已經(jīng)解決啦！以后發(fā)帖會注意要問的問題，多謝多謝

帳號		自動登錄	找回密碼
密碼			立即注冊