新手求解單片機(jī)矩陣鍵盤

ID:1100223 · 發(fā)表于 2023-11-18 12:42

第一個程序（一共兩個）
這個代碼是單片機(jī)自帶的程序，按下矩陣鍵盤數(shù)碼管可以顯示對應(yīng)數(shù)字。還有一個我改的，數(shù)碼管卻不亮了。附件有開發(fā)板原理圖，兩個代碼編譯都沒問題，求解，謝謝了。圖片就是原理圖了，不用下載附件了.

#include "reg52.h"

#define uint unsigned int ;
#define uchar unsigned char ;

#define GPIO_DIG P0
#define GPIO_KEY P1

uchar KeyValue;
uchar temp;
uchar i;

uchar code smgduan[16]={0xc0,0xf9,0xa4,0xb0,0x99,0x92,0x82,0xf8,
                                    0x80,0x90,0x88,0x83,0xc6,0xa1,0x86,0x8e}
void delay(unsigned int i)  //延時(shí)函數(shù)
{
      while(i--);
}
void KeyDown(void)
{

      char a=0;
      GPIO_KEY=0x0f;
      if(GPIO_KEY!=0x0f
      {
            delay(1000)；
            if(GPIO_KEY!=0x0f
            {

                     GPIO_KEY=0X0F;
                     switch(GPIO_KEY)
                     {
                              case(0X07):       KeyValue=0;break;
                              case(0X0b):       KeyValue=1;break;
                              case(0X0d):    KeyValue=2;break;
                              case(0X0e):       KeyValue=3;break;
                     }

                     GPIO_KEY=0XF0;
                     switch(GPIO_KEY)
                     {
                              case(0X70):       KeyValue=KeyValue;break;
                              case(0Xb0):       KeyValue=KeyValue+4;break;
                              case(0Xd0): KeyValue=KeyValue+8;break;
                              case(0Xe0):       KeyValue=KeyValue+12;break;
                     }
                     while((a<50)&&(GPIO_KEY!=0xf0)
                     {
                              delay(1000);
                              a++;
                     }
            }
      }
}

void main()
{

      while(1)
      {
            KeyDown();
            GPIO_DIG=smgduan[KeyValue];
      }
}

#include "reg52.h"
#include <intrins.h>

#define uint unsigned int ;
#define uchar unsigned char ;

#define GPIO_DIG P0
#define GPIO_KEY P1
sbit L0=P1^3;
sbit L1=P1^2;
sbit L2=P1^1;
sbit L3=P1^0;

uchar KeyValue;
uchar temp;
uchar i;

uchar code smgduan[16]={0xc0,0xf9,0xa4,0xb0,0x99,0x92,0x82,0xf8,
                                    0x80,0x90,0x88,0x83,0xc6,0xa1,0x86,0x8e}；
void delay(unsigned int i)
{
      while(i--);
}
void KeyDown(void)
{
      while(1)
      {
            P1=0x7f;
            for(i=0;i<=3;i++)
            {
                     if(L0==0) KeyValue=i*4+0;
                     if(L1==0) KeyValue=i*4+1;
                     if(L2==0) KeyValue=i*4+2;
                     if(L3==0) KeyValue=i*4+3;
                     temp=P1;
                     temp=_cror_(temp,1);
                     P1=temp;
            }
      }
}

void main()
{

      while(1)
      {
            KeyDown();
            GPIO_DIG=smgduan[KeyValue];
      }
}