單片機(jī)矩陣鍵盤(pán)顯示電路數(shù)碼管顯示是亂碼的情況,怎么辦

ID:1104202 · 發(fā)表于 2023-12-13 22:44

目的：矩陣鍵盤(pán)顯示電路，采用4*4鍵盤(pán)，用4位數(shù)碼管顯示輸入的數(shù)字，依次將輸入數(shù)字組合在一起顯示

單片機(jī)源程序如下:

#include <reg51.h>
unsigned char WEI[]={0x01,0x02,0x04,0x08,0x10,0x20};
unsigned char table[]={0xC0,0xF9,0xA4,0xB0,0x99,0x92,0x82,0xF8,0x80,0x90,0x88,0x83,0xc6,0xa1,0x86,0x8e};
unsigned char a[4] = {0,0,0,0};
unsigned char temp;
unsigned char key();
unsigned char i,n,shu;
void delayms(unsigned int ms);
void keyscan(void);
void shuma(unsigned char par,unsigned char dat)
{
P2 = WEI[par];
P0 = table[dat];
}
void main()
{
i = n = 0;
while(1)
{
shu = key();
if(shu !=17)
{
a[n] = shu;
n++;
if(n>3) n = 0;
}
shuma(i,a[i]);
i++;
if(i>3) i = 0;
delayms(10);
}
}
unsigned char key()
{
unsigned char key1;
key1 = 17;
P3 = 0xEf;
if (P3 != 0xEf)
{
delayms(10);
switch(P3)
{
case 0xE7:key1 = 0;break;
case 0xEB:key1 = 1;break;
case 0xED:key1 = 2;break;
case 0xEE:key1 = 3;break;
}
while(P3 != 0xEf);
}
P3 = 0xDF;
if (P3 != 0xDF)
{
delayms(10);
switch(P3)
{
case 0xD7:key1 = 4;break;
case 0xDB:key1 = 5;break;
case 0xDD:key1 = 6;break;
case 0xDE:key1 = 7;break;
}
while(P3 != 0xDF);
}
P3 = 0xBF;
if (P3 != 0xBF)
{
delayms(10);
switch(P3)
{
case 0xb7:key1 = 8;break;
case 0xBB:key1 = 9;break;
case 0xBD:key1 = 10;break;
case 0xBE:key1 = 11;break;
}
while(P3 != 0xBF);
}
P3 = 0x7f;
if (P3 != 0x7f)
{
delayms(10);
switch(P3)
{
case 0x77:key1 = 12;break;
case 0x7B:key1 = 13;break;
case 0x7D:key1 = 14;break;
case 0x7E:key1 = 15;break;
}
while(P3 != 0x7f);
}
return key1;
}
void delayms(unsigned int ms)
{
unsigned int x,y;
for (x=ms;x>0;x--)
for(y=120;y>0;y--);
}