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現(xiàn)在有一段代碼如下,可以運(yùn)行,功能是讀取時(shí)間,并在屏幕中繪制一個(gè)數(shù)字:
- switch (hour() / 10) {
- case 0:
- {
- display.drawBitmap(0, 16, Number_0, 36, 72, GxEPD_BLACK);
- break;
- }
- case 1:
- {
- display.drawBitmap(0, 16, Number_1, 36, 72, GxEPD_BLACK);
- break;
- }
- case 2:
- {
- display.drawBitmap(0, 16, Number_2, 36, 72, GxEPD_BLACK);
- break;
- }
- case 3:
- {
- display.drawBitmap(0, 16, Number_3, 36, 72, GxEPD_BLACK);
- break;
- }
- case 4:
- {
- display.drawBitmap(0, 16, Number_4, 36, 72, GxEPD_BLACK);
- break;
- }
- case 5:
- {
- display.drawBitmap(0, 16, Number_5, 36, 72, GxEPD_BLACK);
- break;
- }
- case 6:
- {
- display.drawBitmap(0, 16, Number_6, 36, 72, GxEPD_BLACK);
- break;
- }
- case 7:
- {
- display.drawBitmap(0, 16, Number_7, 36, 72, GxEPD_BLACK);
- break;
- }
- case 8:
- {
- display.drawBitmap(0, 16, Number_8, 36, 72, GxEPD_BLACK);
- break;
- }
- case 9:
- {
- display.drawBitmap(0, 16, Number_9, 36, 72, GxEPD_BLACK);
- break;
- }
- }
復(fù)制代碼 這當(dāng)中使用到switch語(yǔ)句,而且每個(gè)條件觸發(fā)的命令都類似。但這一大串代碼看起來(lái)很臃腫,我想將其改成以下形式:
- //建立一個(gè)數(shù)組
- NUM_NAMES[] = { Number_0, Number_1, Number_2, Number_3, Number_4, Number_5, Number_6, Number_7, Number_8, Number_9 };
- display.drawBitmap(0, 16, NUM_NAMES[(hour() / 10)], 36, 72, GxEPD_BLACK);
復(fù)制代碼 上方代碼并不能正常運(yùn)行,NUM_NAMES數(shù)組不能被正確調(diào)用。
現(xiàn)在問(wèn)題是,這一個(gè)數(shù)組要怎么建立才合理呢?
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