關(guān)于51單片機(jī)逆變器通過負(fù)載的電壓和電流不穩(wěn)

ID:1116897 · 發(fā)表于 2024-4-16 20:40

大家好，這是一個(gè)逆變器程序，從p2.0和2.1生成spwm波通過ir2101驅(qū)動(dòng)四個(gè)開關(guān)管，
波形應(yīng)該是正確的，但是問題是通過負(fù)載的電壓和電流不穩(wěn)，弄了很長時(shí)間，網(wǎng)上也搜不到可以問問各位我這是代碼還是電路有問題
單片機(jī)源程序如下:

#include "reg52.h"
#define uchar signed int
signed int code spwm [200]={40,42,43,44,45,47,48,49,50,51,53,54,55,56,57,58,60,61,62,63,64,65,66
,67,68,69,69,70,71,72,73,73,74,75,75,76,76,77,77,78,78,79,79,79,79,80
,80,80,80,80,80,80,80,80,80,79,79,79,78,78,78,77,77,76,76,75,75,74,73
,72,72,71,70,69,68,67,66,65,64,63,62,61,60,59,58,57,56,55,53,52,51,50
,48,47,46,45,43,42,41,39,38,37,35,34,33,32,30,29,28,27,25,24,23,22,21
,20,19,18,17,16,15,14,13,12,11,10,9,8,8,7,6,5,5,4,4,3,3,2
,2,2,1,1,1,0,0,0,0,0,0,0,0,0,0,1,1,1,1,2,2,3,3
,4,4,5,5,6,7,7,8,9,10,11,11,12,13,14,15,16,17,18,19,20,22,23
,24,25,26,27,29,30,31,32,33,35,36,37,38,40};
uchar count,m,i,j ;
uchar T;
sbit pwm1=P2^0;
sbit pwm2=P2^1 ;
void main (void){
m=0;
TMOD=0x02 ;
TH0=(65536-100)/256;
TL0= (65536-100) %256;
EA=1 ;
ET0=1;
TR0=1;
count=40 ;
T=1;
i=0;
while(1) ;
}
void time0()interrupt 1
{
m++;
if (count<=spwm[i])
{pwm2=0x00;
for(j=5;j>0;j--);
pwm1=0Xff ;
}
if (count>spwm[i])
{pwm1=0X00;
for(j=5;j>0;j--) ;
pwm2=0Xff ;
}
if (m==2)
{i++ ;
if (i==200)
{i=0;
}
m=0;
}
if (T==1)
{
count=count+10;
if (count==80)
{
T=0;
}
}
else
{
count=count-10;
if (count==0)
{
T=1;
}
}