自建24點(diǎn)陣數(shù)字字庫(kù)顯示不正常

ID:570252 · 發(fā)表于 2024-5-25 10:10

各位大佬，

前些天在用LCD0802做頻率計(jì)，總覺得顯示不好看，想改用12864（12832比較難買）。碰到的問題是用16點(diǎn)陣字體太小，一屏四行也用不完，想改成24點(diǎn)陣的。用PCTOLCD2000建了只0-9再加上小數(shù)點(diǎn)的小字庫(kù)，如下：
const unsigned char code F12X24[][36]=
{
{0x00,0x00,0x00,0x00,0x7F,0x80,0x01,0xFF,0xE0,0x03,0x80,0x70,0x06,0x00,0x18,0x04},
{0x00,0x08,0x04,0x00,0x08,0x06,0x00,0x18,0x03,0x80,0x70,0x01,0xFF,0xE0,0x00,0x7F},
{0x80,0x00,0x00,0x00},/*"0",0*/
{0x00,0x00,0x00,0x00,0x00,0x00,0x02,0x00,0x08,0x02,0x00,0x08,0x02,0x00,0x08,0x03},
{0xFF,0xF8,0x07,0xFF,0xF8,0x00,0x00,0x08,0x00,0x00,0x08,0x00,0x00,0x08,0x00,0x00},
{0x00,0x00,0x00,0x00},/*"1",1*/
{0x00,0x00,0x00,0x01,0xC0,0x18,0x02,0xC0,0x38,0x04,0x00,0x48,0x04,0x00,0x88,0x04},
{0x03,0x08,0x04,0x06,0x08,0x06,0x0C,0x08,0x03,0xF8,0x08,0x01,0xE0,0x78,0x00,0x00},
{0x00,0x00,0x00,0x00},/*"2",2*/
{0x00,0x00,0x00,0x03,0x80,0x70,0x03,0x80,0x70,0x04,0x00,0x08,0x04,0x08,0x08,0x04},
{0x08,0x08,0x06,0x18,0x08,0x03,0xF4,0x18,0x01,0xE7,0xF0,0x00,0x01,0xE0,0x00,0x00},
{0x00,0x00,0x00,0x00},/*"3",3*/
{0x00,0x00,0x00,0x00,0x03,0x00,0x00,0x05,0x00,0x00,0x19,0x00,0x00,0x21,0x00,0x00},
{0xC1,0x08,0x01,0x01,0x08,0x07,0xFF,0xF8,0x07,0xFF,0xF8,0x00,0x01,0x08,0x00,0x01},
{0x08,0x00,0x01,0x00},/*"4",4*/
{0x00,0x00,0x00,0x00,0x00,0xE0,0x07,0xFC,0xD0,0x04,0x08,0x08,0x04,0x10,0x08,0x04},
{0x10,0x08,0x04,0x10,0x08,0x04,0x18,0x38,0x04,0x0F,0xF0,0x04,0x07,0xC0,0x00,0x00},
{0x00,0x00,0x00,0x00},/*"5",5*/
{0x00,0x00,0x00,0x00,0x3F,0x80,0x01,0xFF,0xE0,0x03,0x84,0x30,0x02,0x08,0x18,0x04},
{0x10,0x08,0x04,0x10,0x08,0x04,0x10,0x08,0x07,0x18,0x10,0x03,0x0F,0xF0,0x00,0x07},
{0xC0,0x00,0x00,0x00},/*"6",6*/
{0x00,0x00,0x00,0x00,0x00,0x00,0x03,0x80,0x00,0x06,0x00,0x00,0x04,0x00,0x00,0x04},
{0x00,0xF8,0x04,0x07,0xF8,0x04,0x18,0x00,0x04,0xE0,0x00,0x07,0x00,0x00,0x06,0x00},
{0x00,0x00,0x00,0x00},/*"7",7*/
{0x00,0x00,0x00,0x01,0xC1,0xE0,0x03,0xF3,0xF0,0x06,0x36,0x10,0x04,0x18,0x08,0x04},
{0x08,0x08,0x04,0x0C,0x08,0x04,0x0C,0x08,0x06,0x16,0x18,0x03,0xF3,0xF0,0x01,0xC1},
{0xE0,0x00,0x00,0x00},/*"8",8*/
{0x00,0x00,0x00,0x00,0xF8,0x00,0x03,0xFC,0x30,0x03,0x06,0x38,0x04,0x02,0x08,0x04},
{0x02,0x08,0x04,0x02,0x08,0x04,0x04,0x10,0x03,0x08,0xF0,0x01,0xFF,0xC0,0x00,0x7F},
{0x00,0x00,0x00,0x00},/*"9",9*/
};

顯示函數(shù)如下（24點(diǎn)陣）：

else if(Char_Size ==24)
            {
               c=chr-'/';
   OLED_Set_Pos(x, y);
      for (i = 0; i < 12; i++)
         OLED_WR_Byte(F12X24[c * 36 + i], OLED_DATA);  //18*2
      OLED_Set_Pos(x, y + 1);
      for (i = 0; i < 12; i++)
         OLED_WR_Byte(F12X24[c * 36 + i +12], OLED_DATA);
         OLED_Set_Pos(x, y + 2);
      for (i = 0; i < 12; i++)
         OLED_WR_Byte(F12X24[c * 36 + i +24], OLED_DATA);

}

其中c=chr-'/'是取偏移后的值。因?yàn)樾∽謳?kù)的第一位是‘0’，ASC值48，而‘/'是47，48-47=1，正好取首字符。

工作時(shí)16點(diǎn)陣正常，但在24點(diǎn)陣時(shí)僅能顯示24點(diǎn)陣麻點(diǎn)方塊，不是所需數(shù)字。

我對(duì)C語(yǔ)言的底層編程不內(nèi)行，故特地向各位請(qǐng)教。

謝謝。

ID:69038 · 發(fā)表于 2024-5-25 15:03

“其中c=chr-'/'是取偏移后的值。因?yàn)樾∽謳?kù)的第一位是‘0’，ASC值48，而‘/'是47，48-47=1，正好取首字符�！�
總感覺哪里不對(duì)

ID:570252 · 發(fā)表于 2024-5-25 16:39

zhuls 發(fā)表于 2024-5-25 15:03
“其中c=chr-'/'是取偏移后的值。因?yàn)樾∽謳?kù)的第一位是‘0’，ASC值48，而‘/'是47，48-47=1，正好取首字符 ...

你好，謝謝關(guān)注。
在一般西文字庫(kù)里，大都會(huì)從 ‘ ’ 開始，即從 ‘ ’ - ‘~’，并按ASCII值排列，因此偏移值要減去 ‘ ’（ASCII值32)，即 c=chr-' ’ ，即可得到所需顯示字符在字庫(kù)里的位置。但我的字庫(kù)里只有11個(gè)數(shù)字（多了內(nèi)存不夠），所以就自作聰明，減去 ‘/' 字符的ASCII值（47）了。

ID:69038 · 發(fā)表于 2024-5-25 17:29

bobby_jack 發(fā)表于 2024-5-25 16:39
你好，謝謝關(guān)注。
在一般西文字庫(kù)里，大都會(huì)從 ‘ ’ 開始，即從 ‘ ’ - ‘~’，并按ASCII值排列，因此 ...

理是這個(gè)理，要是顯示‘0’時(shí)，你-47，能對(duì)的上嗎？我覺得既然你的小字庫(kù)是0~9，那么首字當(dāng)是‘0’，偏移量就應(yīng)該是‘0’，即0x30,你用這個(gè)‘/’（0x2F）做偏移量真的對(duì)嗎？

void OLED_ShowChar(u8 x,u8 y,u8 chr)
{
unsigned char c=0,i=0;
<font color="#ff0000"> c=chr-' ';//得到偏移后的值 //字庫(kù)從' '空格開始，偏移量就該是‘ ’空格的ASC碼</font>
if(x>Max_Column-1){x=0;y=y+2;}
if(SIZE ==16)
{
OLED_Set_Pos(x,y);
for(i=0;i<8;i++)
OLED_WR_Byte(F8X16[c*16+i],OLED_DATA);
OLED_Set_Pos(x,y+1);
for(i=0;i<8;i++)
OLED_WR_Byte(F8X16[c*16+i+8],OLED_DATA);
}
else {
OLED_Set_Pos(x,y+1);
for(i=0;i<6;i++)
OLED_WR_Byte(F6x8[c][i],OLED_DATA);
}
}

復(fù)制代碼

//常用ASCII表
//偏移量32
const unsigned char code F8X16[]=

ID:570252 · 發(fā)表于 2024-5-25 22:17

zhuls 發(fā)表于 2024-5-25 17:29
理是這個(gè)理，要是顯示‘0’時(shí)，你-47，能對(duì)的上嗎？我覺得既然你的小字庫(kù)是0~9，那么首字當(dāng)是‘0’，偏移 ...

你好，謝謝再次支招。

問題已經(jīng)解決，主要有三點(diǎn)：

第一即是如你所說的應(yīng)該改去‘0’，因?yàn)镃語(yǔ)言都是從0開始計(jì)數(shù)，而我忽略了。

第二是調(diào)用函數(shù)有誤。它是從網(wǎng)上摘錄下來的，估計(jì)發(fā)布者也沒有對(duì)此驗(yàn)證。正確的寫法應(yīng)該是：

else if(Char_Size ==24)
{
if(x>Max_Column-1){x=0;y=y+2;}
c=chr-'0';
OLED_Set_Pos(x, y);
for (i = 0; i < 12; i++)
OLED_WR_Byte(F12X24[c] [i], OLED_DATA);
OLED_Set_Pos(x, y + 1);
for (i = 0; i < 12; i++)
OLED_WR_Byte(F12X24[c] [i +12], OLED_DATA);
OLED_Set_Pos(x, y + 2);
for (i = 0; i < 12; i++)
OLED_WR_Byte(F12X24[c] [i +24], OLED_DATA);
}

復(fù)制代碼

即F12X24本身是二維的，而在原程序調(diào)用時(shí)寫成一維。

第三是pctolcd取模時(shí)在正向，而我用反了。

再次謝謝。

帳號(hào)		自動(dòng)登錄	找回密碼
密碼			立即注冊(cè)