|
|
#include<reg52.h>
#define uchar unsigned char
#define uint unsigned int
sbit dula=P2^6;
sbit wela=P2^7;
sbit led1=P1^0;
sbit key=P3^2;
uchar code table[]=
{
0x3f,0x06,0x5b,0x4f,
0x66,0x6d,0x7d,0x07,
0x7f,0x6f,0x77,0x7c,
0x39,0x5e,0x79,0x71
};
void delayms(uint);
void display(uchar,uchar);
uchar num,num1,num2,shi,ge;
void main()
{
TMOD=0x11;
TH0=(65536-45872)/256;
TL0=(65536-45872)%6;
TH1=(65536-45872)/256;
TL1=(65536-45872)%6;
EA=1;
ET0=1;
ET1=1;
TR0=1;
TR1=1;
IT0=1;
EX0=1;
while(1)
{
display(shi,ge);
}
}
void display(uchar shi,uchar ge)
{
dula=1;
P0=table[shi];
dula=0;
P0=0xff,
wela=1;
P0=0xfe;
wela=0;
delayms(5);
dula=1;
P0=table[ge];
dula=0;
P0=0xff;
wela=1;
P0=0xfd;
wela=0;
delayms(5);
}
void delayms(uint xms)
{
uint i,j;
for(i=xms;i>0;i--)
for(j=110;j>0;j--);
}
void int0()interrupt 0
{
num2++;
}
void T0_time() interrupt 1
{ TH0=(65536-45872)/256;
TL0=(65536-45872)%6;
}
void T1_time()interrupt 3
{
TH1=(65536-45872)/256;
TL1=(65536-45872)%6;
if(num2==4)
{
num2=0;
num++;
if(num==100)
num=0;
shi=num/10;
ge=num;
}
}
注：本次實(shí)驗(yàn)結(jié)合之前的單片機(jī)中定時(shí)計(jì)數(shù)器和捕獲兩者的程序，簡易的測算無刷直流電機(jī)的旋轉(zhuǎn)圈數(shù)。無刷直流電機(jī)每旋轉(zhuǎn)一次，將會(huì)有4個(gè)高頻信號(hào)，則單片機(jī)捕獲到4次高頻信號(hào)時(shí)，計(jì)數(shù)器內(nèi)部加1，顯示到譯碼管上。
|
評(píng)分
-
查看全部評(píng)分
|
