分享一個單片機代碼數(shù)碼管從0到9再到0再到9的循環(huán)（歡迎大家提問，及糾正）

ID:205939 · 發(fā)表于 2017-6-2 23:24

實現(xiàn)一個數(shù)碼管從0到9再到0再到9的循環(huán)，每隔1S循環(huán)一次（附件為原理圖）P1接J16，P0接J12

#include "reg51.h"
#define uchar unsigned char
#define uint unsigned int
uchar code table_numberP[] = {0xfe,0xfd,0xfb,0xf7,0xef,0xdf,0xbf,0x7f};
uchar code table[] = {0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d,0x07,0x7f,0x6f,0x77,0x7c,0x39,0x5e,0x79,0x71};
uint n;
uint ge;
void main()
{
ge = 0;
  TMOD = 0x01;
TH0 = (65536-45872)/256;
TL0 = (65536-45872)%256;
EA = 1;
ET0 = 1;
TR0 = 1;
  while(1);
}
void T0_time()interrupt 1
{
TH0 = (65536-45872)/256;
TL0 = (65536-45872)%256;
n++;
if(n%20 == 0)
{

if(ge<=9){

P1 = table_numberP[0];
P0 = table[ge];
ge++;
  if(ge == 10){
ge = 0;
}
}
}
}

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分享一個單片機代碼 數(shù)碼管從0到9再到0再到9的循環(huán)（歡迎大家提問，及糾正）

分享一個單片機代碼數(shù)碼管從0到9再到0再到9的循環(huán)（歡迎大家提問，及糾正）