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回帖獎勵 +13
#include<reg51.h>
sbit dula=P2^6;
sbit wela=P2^7;
#define uchar unsigned char
#define uint unsigned int
uchar j,k,a1,a0,s=60;
uint m;
uchar table[]={0x3f,0x06,0x5b,0x4f,0x66,
0x6d,0x7d,0x07,0x7f,0x6f,0x77,
0x7c,0x39,0x5e,0x79,0x71};
void delay(uchar i)
{
for (j=i;j>0;j--)
for(k=125;k>0;k--);
}
void display(uchar sh,uchar g)
{
P0=0x00;
dula=1;
P0=table[sh];
dula=0;
wela=0;
P0=0xfe;
wela=1;
wela=0;
delay(5);
P0=0x00;
dula=1;
P0=table[g];
dula=0;
P0=0xfd;
wela=1;
wela=0;
delay(5);
}
void time0() interrupt 1
{
TH0=(65536-46080)/256;
TL0=(65536-46080)%256;
m++;
}
void main()
{
TMOD=0x01;
TR0=1;
TH0=(65536-46080)/256;// 我的晶振為11.0592,故所記次數(shù)應(yīng)為46080，
TL0=(65536-46080)%256;
ET0=1;
EA=1;
while(1)
{
if(m==20)
{
m=0;
s--;
}
a0=s%10;
a1=s/10;
display(a1,a0);
if(s==0)
{
TR0=0;
}
}
}
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