如何向 AT24C02 存儲(chǔ) 大于 256 的數(shù)據(jù)

ID:65643 · 發(fā)表于 2014-12-13 12:31

如我要存儲(chǔ) 98888，有辦法嗎？謝謝

ID:1 · 發(fā)表于 2014-12-13 13:37

你可以分成5次來存儲(chǔ)

ID:67796 · 發(fā)表于 2014-12-13 19:24

使用BCD碼，每一位用4個(gè)bits，5個(gè)位建議用3個(gè)字節(jié)。

ID:66032 · 發(fā)表于 2014-12-15 11:26

用最通用的PIC16F877 硬件I2C 要分四次寫入和讀出這個(gè)數(shù)據(jù)，請(qǐng)看下面的source code
#define uint unsigned int
#define ulong unsigned long
uint Databuf1, Databuf2;
ulong Databuf;
void Write_AT24C02(uchar WriteAddr,uchar Databuf)
{
SEN=1;
while(SEN==1);
SSPIF=0;

SSPBUF=0xA0;
while(SSPIF==0);    //?¡à|ì?¡¤¡é?¨a¨a¨o¡à??a?1
SSPIF=0;

SSPBUF=WriteAddr;
while(SSPIF==0);
SSPIF=0;

SSPBUF=Databuf;
while(SSPIF==0);
SSPIF=0;

PEN=1;
while(PEN==1);
SSPIF=0;
}

unsigned Read_AT24C02(uchar Addr)
{
unsigned char buf;
SEN=1;
while(SEN==1);
SSPIF=0;

SSPBUF=0xA0;
while(SSPIF==0);
SSPIF=0;

SSPBUF=Addr;
while(SSPIF==0);
SSPIF=0;

RSEN=1;
while(SSPIF==0);
SSPIF=0;

SSPBUF=0xA1;          //¡¤¡é?¨aAT24C02|ì??¡Â?t|ì??¡¤o¨a?¨￠D?o?
while(SSPIF==0);    //?¡à|ì?¡¤¡é?¨a¨a¨o¡à??a?1
SSPIF=0;             //??SSPIF¡à¨o????

RCEN=1;             //¨|¨¨???¨￠?¨oD¨a
while(SSPIF==0);    //?¡à|ì?¡¤¡é¨a¨o?a?1
buf=SSPBUF;          //?¨￠3?¨oy?Y¡¤?¨¨?buf?D?Y¡ä?
ACKDT=1;             //?¡ä¨¨¡¤¨¨?¨oy?Y??
ACKEN=1;             //¡¤¡é?¨a¨®|¡äeD?o?
while(SSPIF==0);    //?¡à|ì?¡¤¡é?¨a¨a¨o¡à??a?1
SSPIF=0;             //??SSPIF¡à¨o????

PEN=1;                //2¨2¨|¨2IIC¨a¡ê?1D?o?
while(PEN==1);       //?¡à|ì?¨a¡ê?1?a?1
SSPIF=0;             //??SSPIF¡à¨o????

return(buf);          //???¨￠3?¨oy?Y¡¤|ì??
}

Write_AT24C02(0x00,0xff);
Write_AT24C02(0x01,0xff);
Write_AT24C02(0x03,(98888-65536)/256);
Write_AT24C02(0x04,(98888-65536)%256);

Databuf1=Read_AT24C08(0x00);
Databuf1=Databuf<<8|Read_AT24C02(0x01);
Databuf2=Read_AT24C08(0x03);
Databuf2=Databuf<<8|Read_AT24C02(0x04);
Databuf=Databuf1|Databuf2;

ID:66032 · 發(fā)表于 2014-12-15 11:29

掉了一句偽指令： #define uchar unsigned char

ID:66032 · 發(fā)表于 2014-12-15 11:29

掉了一句偽指令： #define uchar unsigned char

ID:66032 · 發(fā)表于 2014-12-15 11:37

筆誤更正
Databuf1=Read_AT24C08(0x00);
Databuf1=Databuf1<<8|Read_AT24C02(0x01);
Databuf2=Read_AT24C08(0x03);
Databuf2=Databuf2<<8|Read_AT24C02(0x04);
Databuf=Databuf1|Databuf2;

ID:66032 · 發(fā)表于 2014-12-15 11:43

筆誤更正
Databuf1=Read_AT24C02(0x00);
Databuf1=Databuf1<<8|Read_AT24C02(0x01);
Databuf2=Read_AT24C02(0x03);
Databuf2=Databuf2<<8|Read_AT24C02(0x04);
Databuf=Databuf1|Databuf2;

ID:135781 · 發(fā)表于 2017-4-8 18:14

就是呀，可以拆開來存儲(chǔ)的

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如何向 AT24C02 存儲(chǔ) 大于 256 的數(shù)據(jù)

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